Find the contact force on the block having mass $1 \mathrm{kg}.$ (Assume wedge to be fixed)

The coefficient of friction of a surface is $\frac{1}{\sqrt{3}}.$ What should be the angle of inclination so that a body placed on the surface just begins to slide down?

The coefficient of static friction, µ_s, between block A of mass 2 kg and the table as shown in the figure is 0.2. What would be the maximum mass value of block B so that the two blocks do not move ? The string and the pulley are assumed to be smooth and massless. (g = 10 m/s²)

A block stays in equilibrium on an inclined plane. It is easiest to push along

A force $P=3mg$ acts on a block of mass $m$ at an angle of $30°$ with horizontal. The friction force between the block and ground (assuming $\mu =$ coefficient of friction between the contacting surface) is

A block is placed on a rough horizontal surface. The minimum force required to slide the block is

The system shown is just on the verge of slipping. The co-efficient of static friction between the block and the table top is