EASY
Earn 100

Find the sum of the lengths of transverse axis and conjugate axis of the hyperbola y2-36x2=36.

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Important Questions on Hyperbola

MEDIUM
The locus of the point of intersection of the straight lines, tx-2y-3t=0 and x-2ty+3=0 tR, is:
HARD
Equation 1r=18+38cosθ represents
MEDIUM
Which of the following is the equation of a hyperbola?
MEDIUM
Let a and b respectively be the semi-transverse and semi-conjugate axes of a standard hyperbola whose eccentricity satisfies the equation 9e2-18e+5=0. If S5, 0 is a focus and 5x=9 is the corresponding directrix of this hyperbola, then a2-b2 is equal to
EASY
If the eccentricity of the hyperbola x2-y2cosec2α=25 is 5 times the eccentricity of the ellipse x2cosec2α+y2=5, then α is equal to
MEDIUM
A hyperbola whose transverse axis is along the major axis of the conic x23+y24=4 and has vertices at the foci of the conic. If the eccentricity of the hyperbola is 32, then which of the following points does not lie on the hyperbola ?
HARD
The foci of the hyperbola 16x2-9y2-64x+18y-90=0 are
MEDIUM
The eccentricity of the hyperbola whose length of the latus rectum is equal to 8 and the length of its conjugate axis is equal to half of the distance between its foci, is
EASY
If the vertices of a hyperbola be at -2, 0 and 2, 0 and one of its foci be at -3, 0, then which one of the following points does not lie on this hyperbola ?
MEDIUM
Let S=x,yR2:y21+r-x21-r=1, where r±1. Then S represents:
EASY
If 5x+9=0 is the directrix of the hyperbola 16x2-9y2=144, then its corresponding focus is:
HARD
Let 0<θ<π2. If the eccentricity of the hyperbola x2cos2θ-y2sin2θ=1 is greater than 2, then the length of its latus rectum lies in the interval:
MEDIUM
If a directrix of a hyperbola centered at the origin and passing through the point 4,-23 is 5x=45 and its eccentricity is e, then:
MEDIUM
The eccentricity of the hyperbola whose length of its conjugate axis is equal to half of the distance between its foci, is
EASY
The latus rectum of the hyperbola 3x2-2y2=6 is
MEDIUM
If equation (10x-5)2+(10y-4)2=λ2(3x+4y-1)2 represents a hyperbola, then
MEDIUM
If e1 and e2 are the eccentricities of a hyperbola 3x2-3y2=25 and its conjugate, then
EASY
The vertices of the hyperbola are at -5,-3 and -5,-1 and the extremities of the conjugate axis are at -7,-2 and -3,-2, then the equation of the hyperbola is
EASY
A hyperbola has its centre at the origin, passes through the point 4, 2 and has transverse axis of length 4 along the x-axis. Then the eccentricity of the hyperbola is:
EASY
The equation of the hyperbola with vertices 3,0,3,0 and semi-latus rectum 4 is given by: