Alpha Question Bank for Engineering: Chemistry>Chapter 10 - Chemical Kinetics>Exercise-2>Q 31

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For a second order reaction plots are made for $\frac{1}{[A]}$ vs time for the reaction, $2 A ⟶$ Product. Pick up the correct sentences. $[K =$ Rate constant of $A]$

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Important Questions on Chemical Kinetics

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Alpha Question Bank for Engineering: Chemistry>Chapter 10 - Chemical Kinetics>Exercise-2>Q 33

In the following gaseous phase first order reaction,

A (g) ⟶ 2 B (g) + C (g)

initial pressure was found to be

400 mm

, and it changed to

1000 mm

after

20 \min .

Then the correct statements are :-

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Alpha Question Bank for Engineering: Chemistry>Chapter 10 - Chemical Kinetics>Exercise-2>Q 34

For the reaction ${CH}_{4} + {Br}_{2} ⟶ {CH}_{3} Br + HBr$ , the experimental data require the following rate equation:

$\frac{d}{dt} [{CH}_{3} Br] = \frac{k_{1} [{CH}_{4}] [{Br}_{2}]}{1 + k_{2} [HBr] / [{Br}_{2}]}$

Which of the following is/are true regarding this?

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Alpha Question Bank for Engineering: Chemistry>Chapter 10 - Chemical Kinetics>Exercise-2>Q 35

A large increase in the rate of a reaction for a rise in temperature is due to

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Alpha Question Bank for Engineering: Chemistry>Chapter 10 - Chemical Kinetics>Exercise-2>Q 37

Rate constant

k

varies with temperature by equation,

\log k (\min^{- 1}) = 5 - \frac{2000}{T (K)}

. We can conclude:

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Alpha Question Bank for Engineering: Chemistry>Chapter 10 - Chemical Kinetics>Exercise-2>Q 38

Select the correct statements:

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Alpha Question Bank for Engineering: Chemistry>Chapter 10 - Chemical Kinetics>Exercise-2>Q 39

Which of the following statements are true regarding the $\log K vs 1 / T$ plot shown in the given diagram?

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Alpha Question Bank for Engineering: Chemistry>Chapter 10 - Chemical Kinetics>Exercise-2>Q 45

Hydrolysis of ester in catalysed by acid. Rate of hydrolysis of ester were obtained initially and after some ester has been hydrolysed as

R_{0}

and

R_{t}

then (same temp.)

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Alpha Question Bank for Engineering: Chemistry>Chapter 10 - Chemical Kinetics>Exercise-3>Q 1

The rate constant for the reaction

2 N_{2} O_{5} ⟶ 4 {NO}_{2} + O_{2},

is

3 \times 10^{- 5} s^{- 1} .

If the rate is

2.4 \times 10^{- 5}

{molL}^{- 1} s^{- 1},

then the concentration of

N_{2} O_{5}

(in

{molL}^{- 1}

) is: