For given pair of numbers, verify that their product = HCF × LCM . 186 , 403

For the given numbers 186 , 403 , we are asked to verify that their product = HCF × LCM . First let us find the HCF of 186 & 403 using division method. ∴ HCF of 186 , 403 = Divisor of the last step = 31 Next, we need to find the LCM of 186 & 403 . It can be found out by short division method. 31 186 , 403 13 6 , 13 3 6 , 1 2 2 , 1 1 , 1 LCM = Product of factors obtained in division ⇒ LCM = 31 × 6 × 13 = 2418 LCM × HCF = 2418 × 31 = 74958 The product of the numbers = 186 × 403 = 74958 We can see that the product of LCM and HCF is equal to the product of the given numbers. Hence, verified that the product of given numbers = HCF × LCM .

For given pair of numbers, verify that their product = HCF × LCM . 186 , 403

For the given numbers 186 , 403 , we are asked to verify that their product = HCF × LCM . First let us find the HCF of 186 & 403 using division method. ∴ HCF of 186 , 403 = Divisor of the last step = 31 Next, we need to find the LCM of 186 & 403 . It can be found out by short division method. 31 186 , 403 13 6 , 13 3 6 , 1 2 2 , 1 1 , 1 LCM = Product of factors obtained in division ⇒ LCM = 31 × 6 × 13 = 2418 LCM × HCF = 2418 × 31 = 74958 The product of the numbers = 186 × 403 = 74958 We can see that the product of LCM and HCF is equal to the product of the given numbers. Hence, verified that the product of given numbers = HCF × LCM .

The product of two numbers is 2560 and their LCM is 320 . Find their HCF.

Given: Product of the two unknown numbers = 2560 LCM of the numbers = 320 We know that, Product of two numbers = HCF × LCM ⇒ 2560 = HCF × 320 ⇒ HCF = 2560 320 ⇒ HCF = 256 32 ⇒ HCF = 16 2 ⇒ HCF = 8 Hence, the HCF of the numbers with product as 2560 and LCM as 320 is 8 .