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For nuclei with A>100,

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Important Points to Remember in Chapter -1 - The Nucleus from H C Verma CONCEPTS OF PHYSICS [VOLUME 2] Solutions

1. Atomic Nucleus:

The average radius of the nucleus may be written as

R=R0A1/3, R0=1.1×10-15 m

A is mass number.

2. Mass Defect and Binding Energy:

The binding energy of nucleus of mass M, is given by B=Zmp+Nmn-Mc2

For a+XY+b

Q-value=Ma+Mx-Mγ-Mbc2

3. Nuclear Reactions:

(i) Alpha - decay process:

XZAz-2A-4Y+He24

Q-value =MXZA-MYZ-2A-4-MH24ec2

(ii) Beta- minus decay:

XZAYZ+1A+β-+v-

Q-value =MXZA-MYZ+1Ac2

(iii) Beta plus decay:

XZAYZ-1A+β++v

Q-value = MXZA-MYZ-1A-2mec2

(iv) When the atomic electron is captured, X-rays are emitted.

XZA+eYZ-1A+v

Q-value =MXZA-MYZ-1Ac2

4. Nuclear Fission:

Discovered by Hahn and Strassmann in 1938. By attack of a particle on a heavy nucleus A>230 and splitting it into two or more lighter nuclei, a certain mass disappears which is obtained in the form of energy.

A+p excited nucleus B+C+Q

5. Nuclear Fusion:

It is the phenomenon of fusing two or more lighter nuclei to form a single heavy nucleus.

A+BC+Q (Energy)

The product C is more stable than the reactants A and B.

mass defect,  Δm=MA+MB-MC

Energy released is E=Δm×931 MeV

The total binding energy and binding energy per nucleon of C, both are more than of A and B.

ΔE=EC-EA+EB

6. Radioactive Decay Law:

(i) In radioactive decay, the number of nuclei at instant t is given by N=N0e-λt, λ- decay constant.

(ii) Activity of sample: A=A0e-λt

(iii) Activity per unit mass is called specific activity.

(iv) Half-life: T1/2=0.693λ

(v) Average life: Tav=T1/20.693

(vi) A radioactive nucleus can decay by two different processes having half-lives t1 and t2 respectively. Effective half-life of the nucleus is given by 1t=1t1+1t2.

(vii) Probability of a nucleus for survival of time t=NN0=N0e-λtN0=e-λt

7. Parallel radioactive disintegration:

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Let the initial number of nuclei of A is N0 then at any time number of nuclei of A,B & C are given by

N0=NA+NB+NC

dNAdt=-ddtNB+NC

A disintegrates into B and C by emitting α, β particle.

Now, dNBdt=-λ1NA and dNcdt=-λ2NA ddtNB+NC=-λ1+λ2NA

dNAdt=-λ1+λ2NA λeff=λ1+λ2 tall=t1t2t1+t2

8. Radioactive Disintegration with Successive Production:

A is being produced at a rate α.

A disintegrates into B.

dNAdt=α-λNA     1

when NA is maximum dNAdt=0 α-λNA=0

NAmax=αλ= rate of productionλ

By equation (1), 0tdNAα-λNA=0tdt, Number of nuclei is NA=αλ1-e-λt

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