The population of six Indian states as estimated in the year 2015 is given below. State Bihar Jharkhand Uttar pradesh Uttarakhand Madhya Pradesh Chattisgarh Population (in lakhs) 820 270 1060 80 600 210 Draw a bar graph to represent the above data.

Given, The population of six Indian states as estimated in the year 2015 . State Bihar Jharkhand Uttar pradesh Uttarakhand Madhya Pradesh Chattisgarh Population (in lakhs) 820 270 1060 80 600 210 To draw a bar graph first we need to choose the scale such that the maximum value 1060 and the minimum value 80 are included. Use equal division of increment of 100 . So, all bar lie between 0 and 1100 . We can draw the bar graph by following the given steps: Step 1.- On a graph paper, draw a horizontal line OX as x- axis and vertical line OY as y -axis. Step 2.- Along OX, write the names of the states at the points that are taken at a uniform gap. Step 3.- Choose the scale: 1 big division = 100 lakhs 1 small division = 10 lakhs Step 4.-Draw bars of equal width on the x- axis. The difference between the two bars should also be the same. We get the following bar graph:

The following table represents the enrolment of new students in a school for five consecutive years. Years 2011 - 12 2012 - 13 2013 - 14 2014 - 15 2015 - 16 Number of students 130 125 115 135 130 Draw a bar graph to represent the given data.

Given, The enrolment of new students in a school for five consecutive years. Years 2011 - 12 2012 - 13 2013 - 14 2014 - 15 2015 - 16 Number of students 130 125 115 135 130 To draw a bar graph first we need to choose the scale such that the maximum number 135 and the minimum number 115 are included. Use equal division of increment of 10 . So, all bar lie between 0 and 140 . We can draw the bar graph by following the given steps: Step 1.- On a graph paper, draw a horizontal line OX as x- axis and vertical line OY as y -axis. Step 2.- Along OX, write the years at the points that are taken at a uniform gap. Step 3.- Choose the scale: 1 big division = 10 students 1 small division = 1 students Step 4.-Draw bars of equal width on the x- axis. The difference between the two bars should also be the same. We get the following bar graph:

The number of shirts manufactured in a factory during six consecutive months is given below. Month March April May June July August Number of shirts manufactured 10000 15000 18000 25000 17000 20000 Draw a bar graph representing the above information.

The number of shirts manufactured in a factory during six consecutive months is given below. Month March April May June July August Number of shirts manufactured 10000 15000 18000 25000 17000 20000 To draw a bar graph first we need to choose the scale such that the maximum value 25000 and the minimum value 10000 are included. Take the graph with intervals, 10000 , 11000 , 12000 , 13000 , 14000 . . . . . . etc..., here we need to use kink sign in the graph because the interval is not uniform, from the zero to 10000 the difference is 10000 . But from 10000 to 11000 the difference is 1000 , hence we need to put kink sign between 0 to 10000 . We can draw the bar graph by following the given steps: Step 1.- On a graph paper, draw a horizontal line OX as x- axis and vertical line OY as y -axis. Step 2.- Along OX, write the names of the month at the points that are taken at a uniform gap. Step 3.- Choose the scale: 1 unit = 1000 Step 4.-Draw bars of equal width on the x- axis. The difference between the two bars should also be the same. We get the following bar graph:

The following table shows the earnings of Mehra and Sons Pvt.Ltd. (in ₹ lakhs) during four consecutive financial years. Year 2012 - 13 2013 - 14 2014 - 15 2015 - 16 Earning (in ₹ lakhs) 115 112 114 120 Draw a bar graph representing the above data.

Given, The earnings of Mehra and Sons Pvt.Ltd. (in ₹ lakh) during four consecutive financial years. Year 2012 - 13 2013 - 14 2014 - 15 2015 - 16 Earning (in ₹ lakhs) 115 112 114 120 To draw a bar graph first we need to choose the scale such that the maximum value 120 and the minimum value 112 are included. Use equal division of increment of 10 . So, all bar lie between 0 and 121 . Take the graph with intervals, 100 , 111 , 112 , 113 , 114 , 115 , 116 , 117 , 118 . . . . . . etc..., here we need to use kink sign in the graph because the interval is not uniform, from the zero to 100 the difference is 100 . But from 100 to 110 the difference is 10 , hence we need to put kink sign between 0 to 100 . We can draw the bar graph by following the given steps: Step 1.- On a graph paper, draw a horizontal line OX as x- axis and vertical line OY as y -axis. Step 2.- Along OX, write the years at the points that are taken at a uniform gap. Choose the scale. 1 unit = 100 lakhs Step 4.-Draw bars of equal width on the x- axis. The difference between the two bars should also be the same. We get the following bar graph:

The mode of transportation used by 2000 students of a school is as follows: Modes of transportation School bus Private bus Private van Auto Metro On foot Cycle Number of students 690 160 450 230 320 80 70 Draw a bar graph to represent the above data.

Given, The modes of transportation used by 2000 students. Modes of transportation School bus Private bus Private van Auto Metro On foot Cycle Number of students 690 160 450 230 320 80 70 To draw a bar graph first we need to choose the scale such that the maximum value 690 and the minimum value 70 are included. Use equal division of increment of 100 . So, all bar lie between 0 and 700 . We can draw the bar graph by following the given steps: Step 1.- On a graph paper, draw a horizontal line OX as x- axis and vertical line OY as y -axis. Step 2.- Along OX, write the modes of transportation at the points that are taken at a uniform gap. Step 3.- Choose the scale: 1 big division = 100 students 1 small division = 10 students Step 4.-Draw bars of equal width on the x- axis. The difference between the two bars should also be the same. We get the following bar graph

The following table shows the temperature in the morning and evening of the first week of March. Days Monday Tuesday Wednesday Thursday Friday Saturday Sunday Temperature in the morning 30 °C 21 °C 17 °C 22 °C 21 °C 17 °C 12 °C Temperature in the evening 22 °C 15 °C 20 °C 22 °C 15 °C 12 °C 8 °C Draw a double bar graph to represent the above data.

Given, The temperature in the morning and evening of the first week of March. Days Monday Tuesday Wednesday Thursday Friday Saturday Sunday Temperature in the morning 30 °C 21 °C 17 °C 22 °C 21 °C 17 °C 12 °C Temperature in the evening 22 °C 15 °C 20 °C 22 °C 15 °C 12 °C 8 °C To draw a double bar graph first we need to choose the scale such that the maximum temperature 30 °C and the minimum temperature 8 °C are included. Use equal division of increment of 2 °C . So, all bar lie between 0 °C and 32 °C . We can draw the double bar graph by following the given steps: Step 1.- On a graph paper, draw a horizontal line OX as x- axis and vertical line OY as y -axis. Step 2.- Along OX, write the days at the points that are taken at a uniform gap. Step 3.- Choose the scale: 1 big division = 2 °C 1 small division = 0 . 2 °C Step 4.-Draw bars of equal width on the x- axis. The difference between the two bars should also be the same. We get the following bar graph:

EASY

7th CBSE

IMPORTANT

Earn 100

For the data $11, 1, 15, 16, 17, 12, 20, 25, 11, 8, 6, 15, 7, 9, 15,$ your friend calculated the median to be $17$ and mode to be $11$ . Check his answer and correct them if required.

Important Questions on Data Handling and Probability

MEDIUM

7th CBSE

IMPORTANT

I Did It>Chapter 15 - Data Handling and Probability>Exercise 15.3>Q 8

The run scored by $11$ players in a cricket match are as follow: $15, 30, 100, 82, 20, 0, 2, 42, 62, 25, 20$ . Find the mean, median and mode of the given data. Are the three same?

EASY

7th CBSE

IMPORTANT

I Did It>Chapter 15 - Data Handling and Probability>Exercise 15.4>Q 1

The population of six Indian states as estimated in the year $2015$ is given below.

State	Bihar	Jharkhand	Uttar pradesh	Uttarakhand	Madhya Pradesh	Chattisgarh
Population (in lakhs)	$820$	$270$	$1060$	$80$	$600$	$210$

Draw a bar graph to represent the above data.

EASY

7th CBSE

IMPORTANT

I Did It>Chapter 15 - Data Handling and Probability>Exercise 15.4>Q 2

The following table represents the enrolment of new students in a school for five consecutive years.

Years	$2011 - 12$	$2012 - 13$	$2013 - 14$	$2014 - 15$	$2015 - 16$
Number of students	$130$	$125$	$115$	$135$	$130$

Draw a bar graph to represent the given data.

MEDIUM

7th CBSE

IMPORTANT

I Did It>Chapter 15 - Data Handling and Probability>Exercise 15.4>Q 3

The number of shirts manufactured in a factory during six consecutive months is given below.

Month	March	April	May	June	July	August
Number of shirts manufactured	$10000$	$15000$	$18000$	$25000$	$17000$	$20000$

Draw a bar graph representing the above information.

MEDIUM

7th CBSE

IMPORTANT

I Did It>Chapter 15 - Data Handling and Probability>Exercise 15.4>Q 4

The following table shows the earnings of Mehra and Sons Pvt.Ltd. (in ₹ lakhs) during four consecutive financial years.

Year	$2012 - 13$	$2013 - 14$	$2014 - 15$	$2015 - 16$
Earning (in ₹ lakhs)	$115$	$112$	$114$	$120$

Draw a bar graph representing the above data.

EASY

7th CBSE

IMPORTANT

I Did It>Chapter 15 - Data Handling and Probability>Exercise 15.4>Q 6

The mode of transportation used by $2000$ students of a school is as follows:

Modes of transportation	School bus	Private bus	Private van	Auto	Metro	On foot	Cycle
Number of students	$690$	$160$	$450$	$230$	$320$	$80$	$70$

Draw a bar graph to represent the above data.

EASY

7th CBSE

IMPORTANT

I Did It>Chapter 15 - Data Handling and Probability>Exercise 15.4>Q 7

The following table shows the temperature in the morning and evening of the first week of March.

Days	Monday	Tuesday	Wednesday	Thursday	Friday	Saturday	Sunday
Temperature in the morning	$30$ °C	$21$ °C	$17$ °C	$22$ °C	$21$ °C	$17$ °C	$12$ °C
Temperature in the evening	$22$ °C	$15$ °C	$20$ °C	$22$ °C	$15$ °C	$12$ °C	$8$ °C

Draw a double bar graph to represent the above data.

EASY

7th CBSE

IMPORTANT

I Did It>Chapter 15 - Data Handling and Probability>Exercise 15.4>Q 8

A survey was conducted in a class to find the preference of students for fruit drinks and the following tally was collected.

Complete the data by filling the third column and then draw a bar graph with the appropriate scale.

Fruit Juice	Students who preferred	Number of students who preferred
Apple	$\| \| \| \| \| \| \| \|$ $\| \|$	$_____$
Orange	$\| \| \| \|$ $\| \| \| \|$ $\| \| \| \|$ $\| \| \| \|$ $\| \| \| \|$	$_____$
Mango	$\| \| \| \| \| \| \| \| \| \| \| \| \| \| \|$	$_____$
Pomegranate	$\| \| \| \| \| \| \| \| \| \| \| \| \|$	$_____$
Sugarcane	$\| \| \| \| \| \| \| \|$	$_____$

For the data 11, 1, 15, 16, 17, 12, 20, 25, 11, 8, 6, 15, 7, 9, 15, your friend calculated the median to be 17 and mode to be 11. Check his answer and correct them if required.

Important Questions on Data Handling and Probability

Learn and Prepare for any exam you want !

For the data $11, 1, 15, 16, 17, 12, 20, 25, 11, 8, 6, 15, 7, 9, 15,$ your friend calculated the median to be $17$ and mode to be $11$ . Check his answer and correct them if required.