For the reaction, 3A + 2B → C + D , the differential rate law can be written as :

- 1 3 d A dt = d C dt = k A n B m

+ 1 3 d A dt = - d C dt = k A n B m

1 3 d A dt = d C dt = k A n B m

N O 2 required for a reaction is produced by the decomposition of N 2 O 5 in C C l 4 as per the equation, 2 N 2 O 5 g → 4 N O 2 g + O 2 g . The initial concentration of N 2 O 5 is 3.00 m o l L - 1 and it is 2.75 m o l L - 1 after 30 minutes. The rate of formation of N O 2 is:

1.667 × 10 - 2 m o l L - 1 m i n - 1

8.333 × 10 - 3 m o l L - 1 m i n - 1

4.167 × 10 - 3 m o l L - 1 m i n - 1

2.083 × 10 - 3 m o l L - 1 m i n - 1

HARD

JEE Main

IMPORTANT

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For the following graphs,

Choose from the options given below, the correct one regarding order of reaction is :

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Important Questions on Chemical Kinetics

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 10 - Chemical Kinetics>JEE Main - 25 Feb 2021 Shift 1>Q 52

For the reaction, $aA + bB \to cC + dD,$ the plot of $\log k$ v/s $\frac{1}{T}$ is given below:

Question Image

The temperature at which the rate constant of the reaction is $10^{- 4} s^{- 1}$ is _____ $K .$
(Rounded-off to the nearest integer) [Given : The rate constant of the reaction is $10^{- 5} s^{- 1}$ at $500 K$ .]

HARD

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IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 10 - Chemical Kinetics>JEE Main - 24 Feb 2021 Shift 1>Q 54

Gaseous cyclobutene isomerizes to butadiene in a first order process which has a '

K

' value of

3.3 \times 10^{- 4} s^{- 1}

153 ° C .

The time in minutes it takes for the isomerization to proceed

40 %

to completion at this temperature is_____. (Rounded off to the nearest integer)

EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 10 - Chemical Kinetics>JEE Main - 19th April 2014>Q 59

For the reaction,

3A + 2B \to C + D

, the differential rate law can be written as :

EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 10 - Chemical Kinetics>JEE Main - 16th April 2018>Q 60

If 50 % of a reaction occurs in 100 second and 75 % of the reaction occurs in 200 second, the order of this reaction is:

HARD

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 10 - Chemical Kinetics>JEE Main - 15th April 2018>Q 61

N_{2} O_{5}

decomposes to

{NO}_{2}

and

O_{2}

follows the first order kinetics. After

50

minutes, the pressure inside the vessel increases from

50 mm Hg

87.5 mm Hg

. The pressure of the gaseous mixture after

100

minutes at constant temperature will be:

EASY

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IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 10 - Chemical Kinetics>JEE Main - 12th January 2019 Shift 1>Q 63

Decomposition of

X

exhibits a rate constant of

0 .05 μg / year

. How many years are required for the decomposition of

5 μg

X

into

2 .5 μg

EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 10 - Chemical Kinetics>JEE Main - 12th April 2019 Shift 2>Q 64

N O_{2}

required for a reaction is produced by the decomposition of

N_{2} O_{5}

C C l_{4}

as per the equation,

2 N_{2} O_{5} (g) \to 4 N O_{2} (g) + O_{2} (g) .

The initial concentration of

N_{2} O_{5}

3.00 m o l L^{- 1}

and it is

2.75 m o l L^{- 1}

after 30 minutes. The rate of formation of

N O_{2}

is:

EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 10 - Chemical Kinetics>JEE Main - 11th April 2015>Q 66

A + 2 B \to C

, the rate equation for the reaction is given as

Rate

= k [A] [B]

If the concentration of A is kept the same but that of B is doubled what will happen to the rate itself?

For the following graphs, Choose from the options given below, the correct one regarding order of reaction is :

Important Questions on Chemical Kinetics

Learn and Prepare for any exam you want !

For the following graphs,

Choose from the options given below, the correct one regarding order of reaction is :