Name: Elevation in Boiling Point
Uploaded: 2019-07-19
Duration: 7 min 28 s
Description: The boiling point of a liquid is the temperature at which its vapour pressure becomes equal to atmospheric pressure. Let’s learn about the elevation in boili...

Question

Four solutions

A, B, C,

and

D

contain

1 g

each of

HCl, {HNO}_{3}, H_{2} {SO}_{4},

and

H_{3} {PO}_{4}

respectively per

100 mL

. Arrange the solutions in the increasing order of their molarity and normality

Accepted Answer

Given:
Mass of $HCl, {HNO}_{3}, H_{2} {SO}_{4},$ and $H_{3} {PO}_{4} = 1 g$
The volume of solution, $V = 100 mL = 0.1 L$

The molar mass of $HCl = (1 + 35.5) = 36.5 g {mol}^{- 1}$

The equivalent mass of an acid $= \frac{molar mass of the acid}{basicity of the acid}$

The equivalent mass of $HCl = \frac{36.5}{1} g {eq}^{- 1}$

The molar mass of ${HNO}_{3} = (1 + 14 + 3 \times 16) = 63 g {mol}^{- 1}$

The equivalent mass of $100 mL$

The molar mass of $H_{2} {SO}_{4} = (2 \times 1 + 32 + 4 \times 16) = 98 g {mol}^{- 1}$

The equivalent mass of $H_{2} {SO}_{4} = \frac{98}{2} = 49 g {eq}^{- 1}$

The molar mass of $H_{3} {PO}_{4} = (3 \times 1 + 31 + 4 \times 16) = 98 g {mol}^{- 1}$

The equivalent mass of $H_{3} {PO}_{4} = \frac{98}{3} g {eq}^{- 1}$

The molarity of solution $A = \frac{number of moles of solute}{Volume of solution (L)} = \frac{mass of solute}{molar mass of solute \times Volume of solution (L)} = \frac{1 g}{36.5 g {mol}^{- 1} \times 0.1 L} = 0.274 M$

Similarly, the molarity of solution $B = \frac{1 g}{63 g {mol}^{- 1} \times 0.1 L} = 0.159 M$

The molarity of solution $C = \frac{1 g}{98 g {mol}^{- 1} \times 0.1 L} = 0.102 M$

And, the molarity of solution $D = \frac{1 g}{98 g {mol}^{- 1} \times 0.1 L} = 0.102 M$

The normality of solution $A = \frac{Mass of solute}{Equivalent mass of solute \times volume of solution (in L)} = \frac{1}{36.5 \times 0.1} = 0.274 N$

Similarly, the normality of solution $B = \frac{1}{63 \times 0.1} = 0.159 N$

The normality of solution $C = \frac{1}{49 \times 0.1} = 0.204 N$

And, the normality of solution $D = \frac{3}{98 \times 0.1} = 0.306 N$

Hence, the increasing order of molarity for the given four solutions is: $C = D < B < A$ .
And, the increasing order of normality for the given four solutions is: $B < C < A < D$ .

Four solutions $A, B, C,$ and $D$ contain $1 g$ each of $HCl, {HNO}_{3}, H_{2} {SO}_{4},$ and $H_{3} {PO}_{4}$ respectively per $100 mL$ . Arrange the solutions in the increasing order of their molarity and normality

Important Questions on Solutions

Learn and Prepare for any exam you want !

Four solutions A, B, C, and D contain 1 g each of HCl, HNO3, H2SO4, and H3PO4 respectively per 100 mL. Arrange the solutions in the increasing order of their molarity and normality

Important Questions on Solutions

Learn and Prepare for any exam you want !

Four solutions $A, B, C,$ and $D$ contain $1 g$ each of $HCl, {HNO}_{3}, H_{2} {SO}_{4},$ and $H_{3} {PO}_{4}$ respectively per $100 mL$ . Arrange the solutions in the increasing order of their molarity and normality