For the process H 2 O l → H 2 O g at T = 100 o C and 1 atmosphere pressure, the correct choice is-

∆ S s y s t e m > 0 a n d ∆ S s u r r o u n d i n g < 0

∆ S s y s t e m > 0 a n d ∆ S s u r r o u n d i n g > 0

∆ S s y s t e m < 0 a n d ∆ S s u r r o u n d i n g > 0

∆ S s y s t e m < 0 ∆ S s u r r o u n d i n g < 0

EASY

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Free expansion is the expansion of a gas in vacuum. $1 L$ of an ideal gas expands isothermally into vacuum until its total volume is $5 L$ . Calculate the work done and the change in internal energy of the process.

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Important Questions on Thermodynamics

HARD

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

The entropy change associated with the conversion of

1 k g

of ice at

273 K

to water vapours at

383 K

is:

(Specific heat of water liquid and water vapour are

4.2 k J K^{-}

and

2.0 k J K^{- 1} k g^{- 1}

; heat of liquid fusion and vaporization of water are

334 k J k g^{- 1}

and

2491 k J k g^{- 1}

, respectively). (

l o g

273 = 2.436, \log 373 = 2.572, \log 383 = 2.583

)

EASY

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

"Heat cannot be itself flow from a body at lower temperature to a body at higher temperature". This statement corresponds to

HARD

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

One mole of an ideal gas at

300 K

in thermal contact with its surroundings expands isothermally from

1.0 L

2.0 L

against a constant pressure of

3.0 atm

. In this process, the change in entropy of the surroundings

(∆ S_{s u r r})

J K^{- 1}

is:

(1 L atm = 101.3 J)

MEDIUM

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

For which of the following processes,

∆ S

is negative?

EASY

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

State the second law of thermodynamics.

EASY

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

For a sample of perfect gas, when its pressure is changed isothermally from

p_{i}

p_{f}

, the entropy change is given by

EASY

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

An engine operating between the boiling and freezing points of water will have

A. Efficiency more than $27 %$ .

B. Efficiency less than the efficiency of a Carnot engine operating between the same two temperatures.

C. Efficiency equal to $27 %$ .

D. Efficiency less than $27 %$ .

Choose the correct answer from the options given below

EASY

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

In which case change in entropy is negative?

HARD

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

What will be the $Δ H °$ and $Δ S °$ values for the given cell having $E°$ at $20 ° C$ and $30 ° C$ to be $0.18 V$ and $0.28 V$ respectively?

The cell: (Pt) $H_{2} / H^{+} / / KCl / {Hg}_{2} {Cl}_{2} / Hg$ (Given: $1 F = 96500$ Coulombs)

MEDIUM

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

Standard entropies of

X_{2}, Y_{2}

and

{XY}_{3}

are

60, 40

and

50 J / K / mol

respectively. At what temperature the following reaction will be at equilibrium

MEDIUM

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

The entropy change in the isothermal reversible expansion of 2 moles of an ideal gas from 10 to 100 at 300 K is

HARD

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

Two ideal Carnot engines operate in a cascade (all heat given up by one engine is used by the other engine to produce work) between temperatures,

T_{1}

and

T_{2}

. The temperature of the hot reservoir of the first engine is

T_{1}

and the temperature of the cold reservoir of the second engine is

T_{2}

T

is the temperature of the sink of the first engine which is also the source for the second engine. How is

T

related to

T_{1}

and

T_{2}

, if both the engines perform an equal amount of work?

EASY

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

The latent heat of melting of ice at

0 ° C is 6 kJ {mol}^{- 1}

. The entropy change during the melting in

J K^{- 1} {mol}^{- 1}

is closets to-

MEDIUM

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

The process with negative entropy change is:

MEDIUM

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

For the process

H_{2} O (l) \to H_{2} O (g)

T = 100^{o} C

and

1

atmosphere pressure, the correct choice is-

EASY

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

For the reaction,

2 Cl (g) \to {Cl}_{2} (g)

, the correct option is

MEDIUM

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

The true statement amongst the following is:

EASY

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

No process is possible whose sole result is the transfer of heat from a colder object to a hotter object. This is Clausius statement for

MEDIUM

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

For the following reaction

${Fe}_{2} O_{3 (s)} + 3 {CO}_{(g)} ⟶ 2 {Fe}_{(s)} + 3 {CO}_{2 (g)} ΔH ° = - 29.8 kJ$ and $ΔS ° = 15 {JK}^{- 1}$ . What is the value of ${ΔS}_{(total)}$ at $298 K$ ?

MEDIUM

Chemistry>Physical Chemistry>Thermodynamics>Entropy and Second Law of Thermodynamics

Consider the following liquid - vapour equilibrium.

L i q u i d ⇌ V a p o u r

Which of the following relations is correct?

Free expansion is the expansion of a gas in vacuum. 1 L of an ideal gas expands isothermally into vacuum until its total volume is 5 L. Calculate the work done and the change in internal energy of the process.

Important Questions on Thermodynamics

Learn and Prepare for any exam you want !

Free expansion is the expansion of a gas in vacuum. $1 L$ of an ideal gas expands isothermally into vacuum until its total volume is $5 L$ . Calculate the work done and the change in internal energy of the process.