EASY
JEE Main/Advance
IMPORTANT
Earn 100

From the given standard electrode potentials,
Sn4+(aq)+2e-Sn2+(aq)  E°=0.15 V

Br2(l)+2e-2Br-(aq)  E°=1.07 V

The approximate free energy change of the process 2Br-(aq)+Sn4+(aq)Br2(l)+Sn2+(aq) is

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Important Questions on Electrochemistry

MEDIUM
JEE Main/Advance
IMPORTANT
Concentration of K+ ions inside a biological cell was found to be 25 times higher than that outside. The magnitude of the potential difference between the two sides of the cell is close to (2.303 RT/F can be taken as 59 mV; difference in concentrations of other ions can be taken as negligible)
EASY
JEE Main/Advance
IMPORTANT
The standard electrode potential (Eo) of the Daniel cell is 1.1 V Zn(s)+Cu2+(aq)Zn2+(aq)+Cu(s). Under which of the following conditions will the cell potential be higher than 1.1 V?
EASY
JEE Main/Advance
IMPORTANT
The specific conductance of saturated solution of silver bromide is KΩ-1cm-1. The limiting ionic conduction of Ag+ and Br- ions are a and b, respectively. The solubility of AgBr in g lit-1 is:
(Molar mass of AgBr=188 gmol-1)
HARD
JEE Main/Advance
IMPORTANT
The conductance ratio λλ°=0.936 Given this for a certain solution of KCl and λ=122 Ω-1cm2eq-1 and λ+°λ°=0.981.98. Calculate the limiting values of ionic conductance of K and Cl- Ions in Ω-1cm2eq-1.
HARD
JEE Main/Advance
IMPORTANT
Osmotic pressure of 0.1 M weak acid HA is 3 atm. If molar conductance of 0.1 M HA is 30 Ω-1cm2mol-1. Then molar conductance at infinite dilution is:
HARD
JEE Main/Advance
IMPORTANT

Pt,H2 (g)20atm2 M CH3COONH4 (aq)2 M NaCl (aq)H2 (g),Pt20atm

Given pKaCH3COOH=4.74, pKb=NH4OH=4.74

If E is emf of the cell in volt, calculate 1000E. Take: 2.303RTF=0.059

MEDIUM
JEE Main/Advance
IMPORTANT
The metal that cannot be displaced from its aqueous solution by zinc is.
EASY
JEE Main/Advance
IMPORTANT
PQR and S are four metals whose typical reactions are given below:
I Only Q and R react with dilute HCl to give H2 gas.
II When Q is added to a solution containing the ions of the other metals, metallic PR and S are formed?
III P reacts with concentrated HNO3 but S does not.
The correct order of their reducing character is: