EASY
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How does a deflection magnetometer work?

Important Questions on Properties of Magnets and Terrestrial Magnetism

EASY
At a point A on the earth’s surface the angle of dip, δ=+25°. At a point B on the earth’s surface, the angle of dip, δ=-25°. We can interpret that:
MEDIUM
Two bar magnets oscillate in a horizontal plane in earth's magnetic field with time periods of 3 s and 4 s respectively. If their moments of inertia are in the ratio of 3:2 then the ratio of their magnetic moments will be 
MEDIUM
If θ1 and θ2 be the apparent angles of dip observed in two vertical planes at right angles to each other, then the true angle of dip θ is given by
MEDIUM
A jet plane with a wing-span of 25 m is travelling horizontally towards the east with a speed of 3600 km/hour. If the Earth's magnetic field at the location is 4×10-4 T and the angle of dip is 30°, then, the potential difference between the ends of the wing is
HARD
Describe the experiment to compare the magnetic moments of two bar magnets, using deflection magnetometer by deflection method in tan B position under the following heads : Derivation of formula 
EASY
At a certain place, the horizontal component of earth's magnetic field is 13 times the vertical component. The angle of dip at that place is
MEDIUM

A short bar magnet is placed in the magnetic meridian of the earth with North Pole pointing north. Neutral points are found at a distance of 30 cm from the magnet on the East-West line, drawn through the middle point of the magnet. The magnetic moment of the magnet in Am2 is close to:

(Given μ04π=10-7 in SI units and BH= Horizontal component of earth's magnetic field =3.6×10-5 Tesla.)

MEDIUM
What do you mean by the angle of dip at a place? At what place on the earth's surface, the vertical and horizontal components of the earth's magnetic field  be equal?
EASY
From separate magnet method of vibrational magnetometer, describe the method of comparison of magnetic moment of two magnets under the following points : Two precautions 
 
MEDIUM
Describe the experiment to compare the magnetic moments of two bar magnets, using deflection magnetometer by deflection method in tan B position under the following heads : Labelled diagram
HARD
From separate magnet method of vibrational magnetometer, describe the method of comparison of the magnetic moment of two magnets under the following points : Derivation of the formula.
MEDIUM
At certain place, horizontal component is 13 times the vertical component. The angle of dip is
MEDIUM
A magnetic compass needle oscillates 30 times per minute at a place where the dip is 45° and 40 times per minute where the dip is 30°. If B1 and B2 are the net magnetic fields due to the earth at the two places respectively, then the ratio B1B2 is approximately equal to
EASY
A Jet plane is travelling west at 450 metres per second. If the horizontal component of Earth's magnetic field is 4×10-4 Tesla and angle of dip is 30°, Then the vertical component is
MEDIUM
The horizontal component of the earth's magnetic field is 3.6×10- tesla where the dip angle is 60°. The magnitude of the earth's magnetic field is,
HARD
A compass needle of oscillation magnetometer oscillates 20 times per minute at a place P of dip 30°. The number of oscillations per minute become 10 at another place Q of 60° dip. The ratio of the total magnetic field at the two places BQ:BP is:
MEDIUM
From separate magnet method of vibrational magnetometer, describe the method of comparison of the magnetic moment of two magnets under the following points: Observation table 
MEDIUM
The length l of a magnet is large compared to its width and breadth. The time period of its oscillation in a vibration magnetometer is 2 s. The magnet is cut into three equal parts of length l3 each. If these parts are placed on each other with their like poles together, then the time period of this combination is
HARD
To measure the magnetic moment of a bar magnet, one may use