If ${\text{K}}_1$ is ionization constant of ${\text{H}}_2\text{S}\left(\mathrm{aq}\right)\rightleftharpoons 2{\text{H}}^{+}\left(\mathrm{aq}\right)+{\text{S}}^{2-}\left(\mathrm{aq}\right)$ and ${\text{K}}_2$ is that for ${\text{H}}_2\text{S}\left(\mathrm{aq}\right)\rightleftharpoons {\text{H}}^{+}\left(\mathrm{aq}\right)+{\text{HS}}^{-}\left(\mathrm{aq}\right)$, then ionization constant of ${\text{HS}}^{-}\left(\mathrm{aq}\right)\rightleftharpoons {\text{H}}^{+}\left(\mathrm{aq}\right)+{\text{S}}^{2-}\left(\mathrm{aq}\right)$ will be equal to .

(A) $\frac{{\mathrm{K}}_1}{{\mathrm{K}}_2}$

(B) $\frac{{\mathrm{K}}_2}{{\mathrm{K}}_1}$

(C) $\frac{{\mathrm{K}}_1}{\left[{\mathrm{S}}^{2-}\right]}$

Enter the correct answer as A, B or C.