If charge $q$ induced on outer surface of sphere of radius $R$, then intensity at point $P$ at distance $S$ from centre outside of sphere is

Assertion: Electric flux represents the number of electric lines passing normally through the given surface in the electric field.

Reason: Electric flux through a surface is given as $\varphi =\frac{q}{{\epsilon }_0}$.

A cube of side $l$ is placed in a uniform field $E$, where, $E=E\hat{\mathrm{i}}$. The net electric flux through the cube is

A point charge causes an electric flux of $-200 {\text{N m}}^2 {\mathrm{C}}^{-1}$ to pass through spherical Gaussian surface of $10 \mathrm{cm}$ radius centered on the charge. If the radius of the Gaussian surface is doubled, the total electric flux passing through the surface is

A cubical gaussian surface encloses $24 \mathrm{C}$ of charge in its centre. The electric flux through each surface of the cube is

The magnitude of an electric intensity at a point which is at a distance $r$ from the centre of a charged spherical conductor of radius $R$ in terms of the surface charge density $\sigma$ is given by ${}^{\text{'}}E^{\text{'}}$where

The electric field near a conducting surface having a uniform surface charge density $\sigma$ is given by,

An infinite line charge produces a field of $4.5\times {10}^4 \mathrm{N} {\mathrm{C}}^{-1}$ at a distance $2 \mathrm{m}$ from it. The linear charge density is

The electric potential inside a conducting sphere