For each positive real number λ , let A λ be the set of all natural numbers n such that | sin ⁡ ( n + 1 - sin ⁡ n ) | < λ . Let A λ c be the complement of A λ in the set of all natural numbers. Then-

A 1 2 c , A 1 3 c , A 2 5 c are all finite sets

A 1 2 , A 1 3 , A 2 5 are all finite sets

A 1 3 is a finite set but A 1 2 , A 2 5 are infinite sets

A 1 3 , A 2 5 are finite sets and A 1 2 is an infinite set

Let f : R → R be a function such that lim x → ∞ ⁡ f x = M > 0 . Then which of the following is false ?

lim x → ∞ ⁡ x sin ⁡ e - x f x = M

lim x → ∞ ⁡ x sin ⁡ 1 x f x = M

lim x → ∞ ⁡ sin ⁡ f x = sin ⁡ M

lim x → ∞ ⁡ sin ⁡ x x ⋅ f x = 0

MEDIUM

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If f (x) is a differentiable function and $f'' (0) = a$ then $\underset{x \to 0}{l i m} \frac{2 f (x) - 3 f (2 x) + f (4 x)}{x^{2}}$ is

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Important Questions on Differentiation

EASY

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

\lim_{x \to \infty} (\sqrt{x^{2} + 1} - \sqrt{x^{2} - 1})=

HARD

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

The limit

\underset{x \to \infty}{l i m} x^{2} \int_{0}^{x} e^{t^{3} - x^{3}} d t

equals

MEDIUM

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

\lim_{x \to \frac{π}{2}} \frac{\cot x - \cos x}{{(π - 2 x)}^{3}}

equals

EASY

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

\lim_{x \to \infty} \frac{3 x^{3} + 2 x^{2} - 7 x + 9}{4 x^{3} + 9 x - 2}

is equal to

HARD

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

[\cdot]

denote the greatest integer function then

\lim_{n \to \infty} \frac{[x] + [2 x] + \dots . + [n x]}{n^{2}}

is -

EASY

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

\lim_{x \to 0} (\frac{\int_{0}^{x^{2}} \sin \sqrt{t} d t}{x^{2}}) =

HARD

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

For each positive real number

λ,

let

A_{λ}

be the set of all natural numbers

n

such that

| \sin (\sqrt{n + 1} - \sin n) | < λ .

Let

A_{λ}^{c}

be the complement of

A_{λ}

in the set of all natural numbers. Then-

HARD

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

Let

f : R \to R

be a positive increasing function with

\lim_{x \to \infty} \frac{f (3 x)}{f (x)} = 1

. Then,

\lim_{x \to \infty} \frac{f (2 x)}{f (x)}

is equal to

HARD

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

The value of the

\lim_{x \to - \infty} (\sqrt{4 x^{2} - x} + 2 x)

MEDIUM

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

\lim_{x \to \infty} (\sqrt{x + \sqrt{x + \sqrt{x}}} - \sqrt{x})

is equal to

MEDIUM

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

\lim_{x \to 0} \frac{(\sqrt{1 + 2 x}) - 1}{x} =

EASY

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

\underset{x \to \frac{π}{4}}{l i m} \frac{c o t^{3} x - t a n x}{c o s (x + \frac{π}{4})}

EASY

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

f (x) = \sqrt{\frac{x - \sin x}{x + \cos^{2} x}}

,

then

\lim_{x \to \infty} f (x)

is equal to

MEDIUM

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

The value of

\underset{y \to 0}{l i m} \frac{\sqrt{1 + \sqrt{1 + y^{4}}} - \sqrt{2}}{y^{4}}

MEDIUM

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

f

is differentiable at

x = 1

,

then

\lim_{x \to 1} \frac{x^{2} f (1) - f (x)}{x - 1}

HARD

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

Let

f : R \to R

be a function such that

\lim_{x \to \infty} f (x) = M > 0

. Then which of the following is false?

MEDIUM

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

$\lim_{x \to 3} \frac{\sqrt{3 x} - 3}{\sqrt{2 x - 4} - \sqrt{2}}$ is equal to

EASY

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

$\lim_{x \to 0} \frac{{(27 + x)}^{\frac{1}{3}} - 3}{9 - {(27 + x)}^{\frac{2}{3}}}$ equals

MEDIUM

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

$\lim_{x \to 1^{-}} \frac{\sqrt{π} - \sqrt{2 \sin^{- 1} x}}{\sqrt{1 - x}}$ is equal to

MEDIUM

Mathematics>Differential Calculus>Differentiation>L’ Hospital Rule

The value of $\underset{x \to 0}{l i m} \frac{x^{3} c o t x}{1 - c o s x}$

If f (x) is a differentiable function and f′′0=a then limx→02fx-3f2x+f4xx2 is

Important Questions on Differentiation

Learn and Prepare for any exam you want !

If f (x) is a differentiable function and $f'' (0) = a$ then $\underset{x \to 0}{l i m} \frac{2 f (x) - 3 f (2 x) + f (4 x)}{x^{2}}$ is