If the speed of light is 3 . 0 × 10 8 m s - 1 . Calculate the distance covered by light in 2 . 00 ns .

Given : Speed of light = 3 × 10 8 ms − 1 . Time = 2 . 00 ns = 2 × 10 − 9 s . We know, distance = speed × time . Thus, the distance travelled is the product of speed and time. Therefore, distance covered by light = 3 × 10 8 × 2 × 10 - 9 = 0 . 6 m .

If the speed of light is 3 . 0 × 10 8 m s - 1 . Calculate the distance covered by light in 2 . 00 ns .

Given : Speed of light = 3 × 10 8 ms − 1 . Time = 2 . 00 ns = 2 × 10 − 9 s . We know, distance = speed × time . Thus, the distance travelled is the product of speed and time. Therefore, distance covered by light = 3 × 10 8 × 2 × 10 - 9 = 0 . 6 m .

The approximate production of sodium carbonate per month is 424 × 10 6 g , while that of methyl alcohol is 320 × 10 6 g . Which is produced more in terms of moles ?

Given, weight of sodium carbonate = 424 × 10 6 g . Weight of methyl alcohol = 320 × 10 6 g . Molar mass of sodium carbonate Na 2 CO 3 = 2 × 23 + 12 + 3 × 16 = 106 g / mol . Molar mass of methyl alcohol CH 3 OH = 12 × 1 + 16 × 1 + 1 × 4 = 32 g / mol . Number of moles = Given weight Molar mass . Number of moles of sodium carbonate = 424 × 10 6 106 = 4 × 10 6 mol . Number of moles of methyl alcohol = 320 × 10 6 32 = 10 7 mol . Hence, methyl alcohol produced more in terms of moles.