In figure shown, pulleys are ideal. Initially the system is in equilibrium and string connecting $m_2$ to rigid support below is cut. What is the initial acceleration (in $\mathrm{m} {\mathrm{s}}^{-2}$) of  $m_2$? (Given $m_1=9 \mathrm{kg}; m_2=3 \mathrm{kg})$

In the arrangement shown in figure, the string and pulley are light. The car starts moving on the horizontal road with constant velocity $5 \mathrm{m} {\mathrm{s}}^{-1}$ towards left. Speed of $2 \mathrm{kg}$ block in $\mathrm{m} {\mathrm{s}}^{-1}$ when $\theta =60°$is

In the arrangement shown in figure the string and pulley are light. Value of$F$ (in $\mathrm{N}$ ) for which $4 \mathrm{kg}$ block will move with $1 \mathrm{m} {\mathrm{s}}^{-2}$ acceleration in the upward direction is

The frictional force (in $\mathrm{N}$) acting between block and the incline is [Take $g=10 \mathrm{m} {\mathrm{s}}^{-2}$ ]

A force of $10 \mathrm{N}$ is applied on the lower block of mass $5 \mathrm{kg}.$ Acceleration of $5 \mathrm{kg}$ block in $\mathrm{m} {\mathrm{s}}^{-2}$ is $[\mu =0.1]$

A system of $3$ blocks is shown in figure with masses and coefficients of friction indicated in the diagram. What value of maximum horizontal force $F$ can be applied to block $B,$ so that all the three blocks have the same acceleration?

A large box is accelerated up the inclined plane with an acceleration $a_0$ and pendulum is kept vertical (Somehow by an external agent) as shown in figure. Now if the pendulum is set free to oscillate from such position. Then what is the tension in the string immediately after the pendulum is set free (mass of bob $=m$)

A block of mass $m$ is placed over smooth wedge of mass $M$ and a force $F$ is applied on wedge as shown in figure. Find minimum possible value of force $F$ so that resultant force on block $m$ becomes $mg.$