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In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelength in the Balmer series is

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Important Questions on Atomic Physics

EASY
When the electron in hydrogen atom jumps from fourth Bohr orbit to second Bohr orbit, one gets the
MEDIUM
The first member of the Balmer series of hydrogen atom has a wavelength of 6561 A. The wavelength of the second member of the Balmer series (in nm) is_____________
EASY
In Balmer series, wavelength of first line is λ1 and in Brackett series wavelength of first line is λ2 then λ1λ2 is
EASY
Given the value of Rydberg constant is 107 m-1, the wave number of the last line of the Balmer series in hydrogen spectrum will be:
EASY
The ratio of wavelengths of the last line of the Balmer series and the last line of the Lyman series is_____.
MEDIUM
The shortest wavelength of Paschen series in hydrogen spectrum is 8182 A. The first member of the Paschen series is nearly
MEDIUM
Taking the wavelength of first Balmer line in hydrogen spectrum (n=3  to n=2) as 660 nm , the wavelength of the 2nd Balmer line (n = 4  to  n = 2) will be :
EASY
Which of the series of hydrogen atom spectrum lies in the visible region of electromagnetic spectrum?
EASY
In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is:
MEDIUM
If the series limit frequency of the Lyman series is VL, then the series limit frequency of the Pfund series is:
EASY
The series corresponding to lowest wavelength transition in H - atom.
EASY
In Balmer series for hydrogen atom, find the energy of photon corresponding to longest wavelength.
HARD
In hydrogen spectrum, Lα line arises due to transition of electron from the orbit n=3 to the orbit n=2. In the spectrum of singly ionized helium, there is a line having the same wavelength as that of the Lα line of hydrogen. This is due to the transition of the electron from the orbit ______ to ________
MEDIUM
The energy required to ionise a hydrogen like ion in its ground state is 9 Rydbergs. What is the wavelength of the radiation emitted when the electron in this ion jumps from the second excited state to the ground state?
MEDIUM
Hydrogen atom in its ground state is excited by a monochromatic light of energy 13.06eV. The longest wavelength among the spectral lines is (Ionization energy of hydrogen atom is 13.6eV)
MEDIUM
According to Bohr atom model, in which of the following transitions will the frequency be maximum?
MEDIUM
The shortest wave lengths of Paschen, Balmer and Lyman series are in the ratio
EASY
An electron from various excited states of hydrogen atom emit radiation to come to the ground state. Let λn, λg be the de Broglie wavelength of the electron in the nth state and the ground state respectively. Let n be the wavelength of the emitted photon in the transition from the nth state to the ground state. For large n, (A, B are constants)
EASY
The frequency for a series limit of Balmer and Paschen series respectively are f1 and f3. If the frequency of the first line of Balmer series is f2 then the relation between f1, f2 and f3 is
MEDIUM
Hydrogen (1H1), Deuterium (1H2), singly ionised Helium (2He4)+ and doubly ionised lithium (3Li6)++ all have one electron around the nucleus. Consider an electron transition from n=2 to n=1. If the wave lengths of emitted radiation are λ 1 λ 2 λ 3  and λ 4  respectively then approximately which one of the following is correct ?