In which of the following chemical equations, the abbreviations represent the correct states of the reactants and products involved at reaction temperature?

Which of the following shows the given reactions in the increasing order of speed of the reaction?

(i) $2{\mathrm{KClO}}_{3\left(\mathrm{s}\right)}\stackrel{∆}{\to }2{\mathrm{KCl}}_{\left(\mathrm{s}\right)}+3{\mathrm{O}}_{2\left(\mathrm{g}\right)}$

(ii) $2{\mathrm{KClO}}_{3\left(\mathrm{s}\right)}\underset{{\mathrm{MnO}}_2}{\overset{∆}{\to }}2{\mathrm{KCl}}_{\left(\mathrm{s}\right)}+3{\mathrm{O}}_{2\left(\mathrm{g}\right)}$

(iii) $6{\mathrm{CO}}_{2\left(\mathrm{g}\right)} + 6{\mathrm{H}}_2{\mathrm{O}}_{\left(\mathrm{l}\right)}\underset{\mathrm{Chlorophyll}}{\overset{\mathrm{Sunlight}}{\to }}{\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_{6\left(\mathrm{aq}\right)} + 6{\mathrm{O}}_{2\left(\mathrm{g}\right)}$

Given $$\begin{gathered} {{\mathrm{E}}^{\mathrm{o}}}_{{\mathrm{Cr}}^{3+}/\mathrm{Cr}}=-0.74 \mathrm{V}; {{\mathrm{E}}^{\mathrm{o}}}_{{{\mathrm{MnO}}_4}^{-}/{\mathrm{Mn}}^{2+}}=1.51 \mathrm{V} \\ {{\mathrm{E}}^{\mathrm{o}}}_{{\mathrm{Cr}}_2{{\mathrm{O}}_7}^{2-}/{\mathrm{Cr}}^{3+}}=1.33 \mathrm{V}; {{\mathrm{E}}^{\mathrm{o}}}_{\mathrm{Cl}/{\mathrm{Cl}}^{-}}=1.36 \mathrm{V} \end{gathered}$$

Based on the date given above, strongest oxidizing agent will be