In a triangle A B C , right angle at vertex A , if the position vectors of A , B and C are respectively 3 i ^ + j ^ - k ^ , - i ^ + 3 j ^ + p k ^ and 5 i ^ + q j ^ - 4 k ^ , then the point p , q lies on a line:

Making an acute angle with the positive direction of x - a x i s

Making an obtuse angle with the positive direction of x - a x i s

HARD

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Let $\vec{a}, \vec{b}$ and $\vec{c}$ be three vectors such that $|\vec{b}| = 2 |\vec{a}|$ and $|\vec{c}| = 3 |\vec{a}|$ . The Angle between each pair of vectors is $60 °$ such that $|\vec{a} + 2 \vec{b} + 3 \vec{c}| = \sqrt{21}$ then $\sqrt{7} |\vec{c}|$ | is equal to

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Important Questions on Vector Algebra

EASY

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

\vec{x} = 3 \hat{i} - 6 \hat{j} - \hat{k}, \vec{y} = \hat{i} + 4 \hat{j} - 3 \hat{k}

and

\vec{z} = 3 \hat{i} - 4 \hat{j} - 12 \hat{k}

, then the magnitude of the projection of

\vec{x} \times \vec{y}

\vec{z}

HARD

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

Let

\vec{v_{1}}, \vec{v_{2}}, \vec{v_{3}}, \vec{v_{4}}

be unit vectors in the

x y

- plane, one each in the interior of the four quadrants. Which of the following statements is NOT necessarily true?

HARD

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

|\vec{a}| = 2, |\vec{b}| = 3

and

|2 \vec{a} - \vec{b}| = 5,

then

|2 \vec{a} + \vec{b}|

equals :

EASY

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

θ

is the angle between two vectors

\vec{a}

and

\vec{b},

then

\vec{a} \cdot \vec{b} \geq 0

only when

HARD

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

Let

\vec{a} = \hat{i} + \hat{j} + \sqrt{2} \hat{k},

\vec{b} = b_{1} \hat{i} + b_{2} \hat{j} + \sqrt{2} \hat{k}

and

\vec{c} = 5 \hat{i} + \hat{j} + \sqrt{2} \hat{k}

be three vectors such that the projection vector of

\vec{b}

\vec{a}

|\vec{a}|

. If

\vec{a} + \vec{b}

is perpendicular to

\vec{c}

, then

|\vec{b}|

is equal to:

MEDIUM

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

\vec{a}, \vec{b}, \vec{c}

are vectors such that

\vec{a} + \vec{b} + \vec{c} = 0

and

|\vec{a}| = 7, |\vec{b}| = 5, |\vec{c}| = 3

then angle between vector

\vec{b}

and

\vec{c}

MEDIUM

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

Let

\vec{a} = (6 \hat{i} - 3 \hat{j} - 6 \hat{k})

and

\vec{d} = (\hat{i} + \hat{j} + \hat{k})

. Suppose that

\vec{a} = \vec{b} + \vec{c}

where

\vec{b}

is parallel to

\vec{d}

and

\vec{c}

is perpendicular to

\vec{d}

. Then

\vec{c}

is-

EASY

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

If $| \vec{a} | = 10, | \vec{b} | = 2$ and $\vec{a} \cdot \vec{b} = 12$ , then the value of $| \vec{a} \times \vec{b} |$ is

MEDIUM

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

In a parallelogram

A B C D, |\vec{A B}| = a, |\vec{A D}| = b & |\vec{A C}| = c

\vec{D B} \cdot \vec{A B}

has the value:

EASY

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

\vec{a}

and

\vec{b} = 3 \hat{i} + 6 \hat{j} + 6 \hat{k}

are collinear and

\vec{a} . \vec{b} = 27,

then

\vec{a}

is equal to

MEDIUM

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

The projection of the line segment joining the points

(1, - 1, 3)

and

(2, - 4, 11)

on the line joining the points

(- 1, 2, 3)

and

(3, - 2,10)

is _______

MEDIUM

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

If planes

\vec{r} . (p \hat{i} - \hat{j} + 2 \hat{k}) + 3 = 0

and

\vec{r} . (2 \hat{i} - p \hat{j} - \hat{k}) - 5 = 0

include angle

\frac{π}{3}

then the value of

p

EASY

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

\vec{P} and \vec{Q}

are two non-zero vectors inclined to each other at an angle

θ .

\hat{p} and \hat{q}

are unit vectors along

\vec{P} a n d \vec{Q}

respectively. The component of

\vec{Q}

in the direction of

\vec{P}

will be

HARD

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

In a triangle

A B C

, right angle at vertex

A

, if the position vectors of

A, B

and

C

are respectively

3 \hat{i} + \hat{j} - \hat{k}, - \hat{i} + 3 \hat{j} + p \hat{k}

and

5 \hat{i} + q \hat{j} - 4 \hat{k}

, then the point

(p, q)

lies on a line:

HARD

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

Let

\vec{a}, \vec{b}

and

\vec{c}

, be three unit vectors such that

\vec{a} + \vec{b} + \vec{c} = \vec{0}

. If

λ = \vec{a} \cdot \vec{b} + \vec{b} \cdot \vec{c} + \vec{c} \cdot \vec{a}

and

\vec{d} = \vec{a} \times \vec{b} + \vec{b} \times \vec{c} + \vec{c} \times \vec{a}

, then the order pair,

(λ, \vec{d})

, is equal to.

MEDIUM

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

| \vec{a} | = 2, | \vec{b} | = 3

and

\vec{a} \cdot \vec{b} = 4

, then

| \vec{a} - \vec{b} |

is equal to

EASY

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

If the angle between

\vec{a}

and

\vec{b}

\frac{2 π}{3}

and the projection of

\vec{a}

in the direction of

\vec{b}

- 2,

then

| \vec{a} | =

MEDIUM

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

The vectors

3 \vec{a} - 5 \vec{b}

and

2 \vec{a} + \vec{b}

are mutually perpendicular and the vectors

\vec{a} + 4 \vec{b}

and

- \vec{a} + \vec{b}

are also mutually perpendicular. Then the angle between the vectors

\vec{a}

and

\vec{b}

, is

EASY

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

Let

\vec{a} = 2 \hat{i} + λ_{1} \hat{j} + 3 \hat{k}, \vec{b} = 4 \hat{i} + (3 - λ_{2}) \hat{j} + 6 \hat{k}

and

\vec{c} = 3 \hat{i} + 6 \hat{j} + (λ_{3} - 1) \hat{k}

be three vectors such that

\vec{b} = 2 \vec{a}

and

\vec{a}

is perpendicular to

\vec{c} .

Then a possible value of

(λ_{1}, λ_{2}, λ_{3})

EASY

Mathematics>Coordinate Geometry>Vector Algebra>Product of Vectors

What is the length of the projection of

3 \hat{i} + 4 \hat{j} + 5 \hat{k}

on the

x y -

plane?

Let a→, b→ and c→ be three vectors such that b→=2a→ and c→=3a→. The Angle between each pair of vectors is 60° such that a→+2b→+3c→=21 then 7c→ | is equal to

Important Questions on Vector Algebra

Learn and Prepare for any exam you want !

Let $\vec{a}, \vec{b}$ and $\vec{c}$ be three vectors such that $|\vec{b}| = 2 |\vec{a}|$ and $|\vec{c}| = 3 |\vec{a}|$ . The Angle between each pair of vectors is $60 °$ such that $|\vec{a} + 2 \vec{b} + 3 \vec{c}| = \sqrt{21}$ then $\sqrt{7} |\vec{c}|$ | is equal to