Data of a survey is given below,for each type of food calculate the fraction of the total that the data represents.Enter the value in the appropriate column Type of food Number of Calories Fraction of total Degree of Sector Home cooking 1400 Fast food 400 Junk food 200

The table is given as, Type of food Number of Calories Fraction of total Degree of Sector Home cooking 1400 Fast food 400 Junk food 200 From the given table,we can calculate, Total number of calories = 2000 Thus, Fractional part of Home cooking food = N u m b e r o f c a l o r i e s h o m e c o o k i n g f o o d T o t a l n u m b e r o f c a l o r i e s = 1400 2000 = 14 20 = 7 10 Similarly, Fractional part of fast food = 400 2000 = 4 20 = 1 5 Fractional part of junk food = 200 2000 = 2 20 = 1 10 Hence,on putting these values in table, Required table is Type of food Number of Calories Fraction of total Degree of Sector Home cooking 1400 7 10 Fast food 400 1 5 Junk food 200 1 10

In an art competition the marks obtained are given below,from the marks find the mean, Marks 0 greater than 0 10 greater than 10 20 greater than 20 30 greater than 30 40 greater than 40 50 greater than 50 Number of competitors 40 36 22 11 2 0

From the given table, First we convert the marks in class intervals and Cumulative frequency in frequency as shown below, Marks Number of competitors Class interval Class marks x i f i f i x i 0 greater than 0 40 0 - 10 5 4 20 10 greater than 10 36 10 - 20 15 14 210 20 greater than 20 22 20 - 30 25 11 275 30 greater than 30 11 30 - 40 35 9 315 40 greater than 40 2 40 - 50 45 2 90 50 greater than 50 0 50 - 60 55 0 0 ∑ f i = 40 and ∑ f i x 1 = 910 Hence, Mean = ∑ f i x i ∑ f i = 910 40 = 22 . 75 Therefore, Mean of the data is 22 . 75

Solve from the stastical data given below, Class-Interval 5 - 10 10 - 15 15 - 20 20 - 25 25 - 30 30 - 35 35 - 40 40 - 45 Frequency 5 6 15 10 5 4 3 2

Class-Interval 5 - 10 10 - 15 15 - 20 20 - 25 25 - 30 30 - 35 35 - 40 40 - 45 Frequency 5 6 15 10 5 4 3 2 From the given table,we make the following table, Class-interval Mid value x frequency f f x 5 - 10 7 . 5 5 37 . 5 10 - 15 12 . 5 6 75 15 - 20 17 . 5 15 262 . 5 20 - 25 22 . 5 10 225 25 - 30 27 . 5 5 137 . 5 30 - 35 32 . 5 4 130 35 - 40 37 . 5 3 112 . 5 40 - 45 42 . 5 2 85 ∑ f i = 50 and ∑ f i x 1 = 1065 Hence, Mean = ∑ f x ∑ f = 1065 50 = 21 . 3 Therefore, Mean of the data is 21 . 3

EASY

MYP:1

IMPORTANT

Earn 100

List any five characteristics of a good graph.

Important Questions on Data Management Trends in Communities

EASY

MYP:1

IMPORTANT

MYP Mathematics A concept-based approach 1>Chapter 6 - Data Management Trends in Communities>Creating a pie chart by hand>Q 1

Data of a survey is given below,for each type of food calculate the fraction of the total that the data represents.Enter the value in the appropriate column

Type of food	Number of Calories	Fraction of total	Degree of Sector
Home cooking	$1400$
Fast food	$400$
Junk food	$200$

EASY

MYP:1

IMPORTANT

MYP Mathematics A concept-based approach 1>Chapter 6 - Data Management Trends in Communities>Creating a pie chart by hand>Q 2

Data of a survey is given below,for each type of food calculate the fraction of the total that the data represents,multiply each fraction by $360$ .Enter the value in the appropriate column.

Type of food	Number of Calories	Fraction of total	Degree of Sector
Home cooking	$1400$
Fast food	$400$
Junk food	$200$

MEDIUM

MYP:1

IMPORTANT

MYP Mathematics A concept-based approach 1>Chapter 6 - Data Management Trends in Communities>Creating a pie chart by hand>Q 3

In an art competition the marks obtained are given below,from the marks find the mean,

Marks	$0$ greater than $0$	$10$ greater than $10$	$20$ greater than $20$	$30$ greater than $30$	$40$ greater than $40$	$50$ greater than $50$
Number of competitors	$40$	$36$	$22$	$11$	$2$	$0$