Number of $60°$ bond angles in benzene molecule is

${\mathbf{S}}_1:{\mathrm{I}}_3+$ is a linear molecule with two lone pairs of electrons on central atom.
${\mathrm{S}}_2:{\mathrm{I}}_3^{-}$is a linear molecule with three lone pair of electrons on central atom. 
${\mathbf{S}}_3:{\mathrm{IBr}}_4^{+}$ is a bent molecule with two lone pair of electrons on central atom.

${\mathbf{S}}_4:{\mathrm{ICl}}_4-$ is a pyramidal molecule with one lone pair of electrons on central atom.

For ${\mathrm{B}}_2{\mathrm{H}}_6$
${\mathbf{S}}_1:$ Each boron is ${\mathbf{sp}}^3$ hybridized
${\mathbf{S}}_2:$ From terminal '$\mathrm{H}$' & two '$\mathrm{B}$' atom are in same plane but two bridge hydrogen in different plane

${\mathbf{S}}_3:$ It has $4\sigma$ bond $\text{and} 2$ bridge bond