Phenol on reaction with dilute nitric acid, gives two products. Which method will be most efficient for large scale separation?

The intermediate $\mathrm{X}$, in the reaction

In the following reaction :

The compounds $\mathrm{A}$ and $\mathrm{B}$ respectively are

Match List-I with List-II

	List-I		List-II
A		I	${\mathrm{Br}}_2$ in ${\mathrm{CS}}_2$
B		II	${\mathrm{Na}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7/{\mathrm{H}}_2{\mathrm{SO}}_4$
C		III	$\mathrm{Zn}$
D		IV	${\mathrm{CHCl}}_3/\mathrm{NaOH}$

Question: Choose the correct answer from the options given below

The major product $\mathrm{P}$ of the given reaction is (where, $\mathrm{Me}$ is $-{\mathrm{CH}}_3$)

${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6\stackrel{\mathrm{Zymase}}{⟶}\mathrm{A}\underset{∆}{\overset{\mathrm{NaOI}}{\to }}\mathrm{B}+{\mathrm{CHI}}_3$

The number of carbon atoms present in the product $\mathrm{B}$ is

In the given reaction 

the number of ${\mathrm{sp}}^2$ hybridised carbon (s) in compound $\text{'}\mathrm{X}\text{'}$ is _______.