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Planets revolve around the sun in an path.

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Important Questions on Gravitation

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A satellite of mass M is revolving in circular orbit of radius r around the earth. Time of revolution of the satellite is
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If a satellite has to orbit the earth in a circular path every 6hrs, at what distance from the surface of the earth should the satellite be placed (radius of earth =6400 km )
(Assume GM4π2=8×1012Nm2 kg-1,, where G and M are gravitational constant and mass of earth and 101/3=2.1 )
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An artificial satellite of mass m is moving along an elliptical path around the earth. The areal velocity of the satellite is proportional to
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A planet revolving in elliptical orbit has :

A. a constant velocity of revolution.

B. has the least velocity when it is nearest to the sun.

C. its areal velocity is directly proportional to its velocity.

D. areal velocity is inversely proportional to its velocity.

E. to follow a trajectory such that the areal velocity is constant.

Choose the correct answer from the options given below:

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A satellite is in an elliptical orbit around a planet P. It is observed that the velocity of the satellite when it is farthest from the planet is 6 times less than that when it is closest to the planet. The ratio of distances between the satellite and the planet at closest and farthest points is :
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According to Kepler's law, the time period of a satellite varies with its radius as
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A planet is revolving round the sun of mass M in an elliptical orbit with semi-major axis a. The speed of the planet when it is at a distance r from the sun is, (G - Universal gravitational constant)
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The angular momentum of a planet of mass M moving around the sun in an elliptical orbit is L. The magnitude of the areal velocity of the planet is :
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A planet revolves in an elliptical orbit around the sun. The semi-major and semi-minor axes are a and b. Then, the square of time period T is directly proportional to-

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A geostationary satellite orbits around the earth in a circular orbit of radius 36000 km. Then, the time period of a sky satellite orbiting a few 100 km above the earth's surface R=64000 km will approximately be
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Assume that the earth moves around the sun in a circular orbit of radius and there exists a planet that also moves around the sun in a circular orbit with an angular speed twice as large as that of the earth. The radius of the orbit of the planet is,

Assume radius of orbit of planet earth to be R.

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India's Mangalyan was sent to the Mars by launching it into a transfer orbit EOM around the sun. It leaves the earth at E and meets Mars at M. If the semi-major axis of Earth's orbit is a e = 1.5 × 1 0 1 1 m  , that of Mar's orbit a m = 2.28 × 1 0 1 1 m , taking Kepler's laws, give the estimate of time for Mangalyan to reach Mars from Earth.
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A geostationary satellite is orbiting the earth at a height 6R above the surface of the earth, where R is the radius of the earth. The time period of another satellite at a height 2.5R from the surface of the earth is
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A small satellite is in elliptical orbit around the earth as shown in figure. L denotes the magnitude of its angular momentum and Kdenotes its kinetic energy. If 1 and 2 denote two positions of the satellite, then

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The time period of a satellite in a circular orbit of the radius R is T. The period of another satellite in a circular orbit of the radius 9R is:
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A planet is revolving around the sun in which of the following is correct statement?

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The figure shows an elliptical path ABCD of a planet around the sun S such that the area of triangle CSA is 14 the area of the ellipse. (see figure) with DB as the major axis, and CA as the minor axis. If t1 is the time taken for the planet to go over path ABC and t2 for path taken over CDA then:

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Kepler's third law states that the square of the period of revolution T of a planet around the sun is proportional to the third power of the average distance r between sun and planet i.e., T2=Kr3, here K is constant. If the masses of sun and planet are M and m respectively then as per Newton's law of gravitation force of attraction between them is F=GMmr2, here G is gravitational constant. The relation between G and K is described as:
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The time period of a satellite of earth is 5 hr. If the separation between the earth and the satellite is increased to 4 times the previous value, the new time period will become
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According to Kepler, the period of revolution of a planet T and its mean distance from the sun r is related by the equation.