Position - time graph for motion with zero acceleration is

The velocity $\left(v\right)$ and time $\left(t\right)$ graph of a body in a straight line motion is shown in the figure. The point $S$ is at $4.333$ seconds. The total distance covered by the body in $6 \mathrm{s}$ is :

The speed verses time graph for a particle is shown in the figure. The distance travelled (in $\mathrm{m}$) by the particle during the time interval $\mathrm{t}=0$ to $\mathrm{t}=5$ $\mathrm{s}$ will be __________.

The following figure shows the speed-time graph of a particle moving along a fixed direction. The distance travelled by the particle between time $t=0 \mathrm{s}$ to $t=6 \mathrm{s}$ is

The given graph shows the variation of velocity $\left(v\right)$ with position $\left(x\right)$ for a particle moving along a straight line

Which of the following graph shows the variation of acceleration $\left(a\right)$ with position $\left(x\right)?$

A particle starts from the origin at time $t=0$ and moves along the positive $x\mathrm{-}\mathrm{}$axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time $t=5 \mathrm{s}?$

Acceleration-time graph of a body moving in a straight line is as shown in figure. The body started its motion from rest.

At which point is the body moving with the largest speed?

The velocity-time graph of a body moving in a straight line is shown in figure. Find the displacement and distance travelled by the body in $10$ seconds.

If the velocity-time graph has the shape $\mathrm{AMB},$ what would be the shape of the corresponding acceleration-time graph?

The velocity-displacement graph describing the motion of a bicycle is shown in the figure.

The acceleration-displacement graph of the bicycle's motion is best described by :

The velocity time graphs of a car and a scooter are shown in the figure. (i) The difference between the distance travelled by the car and the scooter in 15 s and (ii) the time at which the car will catch up with the scooter are, respectively.