Show that sin A 2 sin B 2 sin C 2 = ∆ 2 a b c s for ∆ A B C , where ∆ is the area of triangle.

Let s be semi-perimeter of the triangle. LHS = sin A 2 sin B 2 sin C 2 = ( s - c ) ( s - b ) b c ( s - c ) ( s - a ) c a ( s - a ) ( s - b ) a b [ from half angle formula ] = ( s - a ) 2 ( s - b ) 2 ( s - c ) 2 ( a b c ) 2 = s 2 ( s - a ) 2 ( s - b ) 2 ( s - c ) 2 s 2 ( a b c ) 2 = s ( s - a ) ( s - b ) ( s - c ) a b c s = Δ 2 a b c s ∵ Δ = s ( s - a ) ( s - b ) ( s - c ) = RHS Hence, proved.

Show that sin A 2 sin B 2 sin C 2 = ∆ 2 a b c s for ∆ A B C , where ∆ is the area of triangle.

Let s be semi-perimeter of the triangle. LHS = sin A 2 sin B 2 sin C 2 = ( s - c ) ( s - b ) b c ( s - c ) ( s - a ) c a ( s - a ) ( s - b ) a b [ from half angle formula ] = ( s - a ) 2 ( s - b ) 2 ( s - c ) 2 ( a b c ) 2 = s 2 ( s - a ) 2 ( s - b ) 2 ( s - c ) 2 s 2 ( a b c ) 2 = s ( s - a ) ( s - b ) ( s - c ) a b c s = Δ 2 a b c s ∵ Δ = s ( s - a ) ( s - b ) ( s - c ) = RHS Hence, proved.

MEDIUM

Earn 100

Show that $\sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2} = \frac{∆^{2}}{a b c s}$ for $∆ A B C$ , where $∆$ is the area of triangle.

Important Questions on Properties of Triangles

HARD

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

In the figure given below, if the areas of the two regions are equal then which of the following is true?

Question Image

HARD

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

Suppose we have two circles of radius $2$ each in the plane such that the distance between their centres is $2 \sqrt{3}$ . The area of the region common to both circles lies between

MEDIUM

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

Consider four triangles having sides

(5, 12, 9), (5, 12, 11), (5, 12, 13)

and

(5, 12, 15)

. Among these the triangle having maximum area has sides

MEDIUM

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

With usual notations, in

∆ A B C

, if

b \cos^{2} \frac{C}{2} + c \cos^{2} \frac{B}{2} = \frac{3 a}{2}

, then

HARD

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

In the figure given below, $A B C D E F$ is a regular hexagon of side length $1$ unit, $A F P S$ and $A B Q R$ are squares. Then the ratio $\frac{area of △ A P Q}{area of △ S R P}$ equals

Question Image

MEDIUM

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

If in a triangle

A B C, a^{2} + 2 b c - (b^{2} + c^{2}) = a b \sin \frac{C}{2} \cos \frac{C}{2}

, then

\cot (B + C) =

MEDIUM

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

Let

X, Y, Z

be respectively the areas of a regular pentagon, regular hexagon and regular heptagon which are inscribed in a circle of radius

1

. Then

MEDIUM

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

A triangle

A B C

has area of

P

square units and circumference

2 S

units. If

h_{1}, h_{2}

and

h_{3}

are respectively the length of the altitudes of the triangle drawn from the vertices

A, B

and

C,

then

P^{2} [\frac{{(h_{1} h_{2} + h_{2} h_{3} + h_{3} h_{1})}^{2}}{h_{1}^{2} h_{2}^{2} h_{3}^{2}} - 2] =

HARD

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

In a rectangle

A B C D,

points

X

and

Y

are the mid-points of

A D

and

D C

respectively. Lines

B X

and

C D

when extended intersect at

E

and lines

B Y

and

A D

when extended intersect at

F

. If the area of rectangle

A B C D

60

square units, then the area of

△ B E F

(in square units) is

HARD

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

Let

A B C D

be a square and let

P

be point on segment

C D

such that

D P : P C = 1 : 2

. Let

Q

be a point on segment

A P

such that

∠ B Q P = 90^{o}

. Then the ratio of the area of quadrilateral

P Q B C

to the area of the square

A B C D

HARD

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

Let

A B C

be a triangle such that

A B = 4, B C = 5

and

C A = 6

. Choose points

D, E, F

A B, B C, C A

respectively, such that

A D = 2, B E = 3, C F = 4

. Then

\frac{area Δ D E F}{area Δ A B C}

HARD

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

Denote Area

(∆ X Y Z), P (∆ X Y Z)

and

|X Y|

by area of the triangle

∆ X Y Z

, perimeter of the triangle

∆ X Y Z

and length of the line segment

X Y

respectively.
Let

A B C D

be a convex quadrangle and the diagonals

A C

and

B D

intersect at

O

. Then

MEDIUM

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

In a

∆ A B C,

a = 2 x, b = 2 y

and

∠ C = 120 °,

then the area of the triangle is

MEDIUM

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

In a $Δ A B C$ , points $X$ and $Y$ are on $A B$ and $A C$ , respectively, such that $X Y$ is parallel to $B C$ . Which of the two following equalities always hold? (Here, $[P Q R]$ denotes the area of $Δ P Q R$ ).

$I$ . $[B C X] = [B C Y]$

$II$ . $[A C X] \cdot [A B Y] = [A X Y] \cdot [A B C]$

MEDIUM

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

a, b, c

are the sides of a

∆ A B C

and exradii

r_{1}, r_{2}, r_{3}

are respectively

12, 6, 4

then

a + 2 b + 3 c =

HARD

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

In a triangle

A B C,

\cot \frac{A}{2} \cot \frac{B}{2} = K,

then all the possible values of

K

lies in

MEDIUM

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

In a

Δ A B C,

4 a = b + c,

then

\tan \frac{B}{2} \tan \frac{C}{2} =

EASY

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

If the sides of triangle are

4, 5

and

6 cm

.

Then the area (in sq cm) of triangle is

MEDIUM

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

In a

∆ A B C

, if

\tan \frac{A}{2} = \frac{5}{6}, \tan \frac{C}{2} = \frac{2}{5}

, then

HARD

Mathematics>Trigonometry>Properties of Triangles>Half-Angle Formula and the Area of a Triangle

Let

x, y

and

z

be positive real numbers. Suppose

x, y

and

z

are the lengths of the sides of a triangle opposite to its angles

X, Y

and

Z

respectively. If

\tan \frac{X}{2} + \tan \frac{Z}{2} = \frac{2 y}{x + y + z}

, then which of the following statements is/are TRUE?

Show that sinA2sinB2sinC2=∆2abcs for∆ABC , where ∆ is the area of triangle.

Important Questions on Properties of Triangles

Learn and Prepare for any exam you want !

Show that $\sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2} = \frac{∆^{2}}{a b c s}$ for $∆ A B C$ , where $∆$ is the area of triangle.