Sketch a graph of resistance versus temperature for a conductor and a superconductor.

Copy and complete table $3$.

Kevlar can be made by reacting $1,4-$diaminobenzene, ${\mathrm{H}}_2\mathrm{N}-{\mathrm{C}}_6{\mathrm{H}}_4-{\mathrm{NH}}_2$, with $1,4-$benzenedicarbonyl chloride, $\mathrm{Cl}-\left(\mathrm{O}\right)\mathrm{C}-{\mathrm{C}}_6{\mathrm{H}}_4-\mathrm{C}\left(\mathrm{O}\right)-\mathrm{Cl}$. Write the equation for the reaction of $\mathrm{n}$ molecules of $1,4-$diaminobenzene reacting with $\mathrm{n}$ molecules of $1,4-$benzenedicarbonyl chloride.

Hydroxyl free-radicals can be generated naturally in the body. This process is catalysed by iron in the following two steps:

Reaction 1: ${\mathrm{Fe}}^{3+}+·{{\mathrm{O}}_2}^{-}\to {\mathrm{Fe}}^{2+}+{\mathrm{O}}_2$.
Reaction 2: ${\mathrm{Fe}}^{2+}+{\mathrm{H}}_2{\mathrm{O}}_2\to {\mathrm{Fe}}^{3+}+·\mathrm{OH}+{\mathrm{OH}}^{-}$.

Use the above information to write the uncatalysed reaction.

Hydroxyl free-radicals can be generated naturally in the body. This process is catalysed by iron in the following two steps:

Reaction 1: ${\mathrm{Fe}}^{3+}+·{{\mathrm{O}}_2}^{-}\to {\mathrm{Fe}}^{2+}+{\mathrm{O}}_2$.
Reaction 2: ${\mathrm{Fe}}^{2+}+{\mathrm{H}}_2{\mathrm{O}}_2\to {\mathrm{Fe}}^{3+}+·\mathrm{OH}+{\mathrm{OH}}^{-}$.

Deduce whether iron is acting as a heterogeneous or homogeneous catalyst and justify your answer.

Hydroxyl free-radicals can be generated naturally in the body. This process is catalysed by iron in the following two steps:

Reaction 1: ${\mathrm{Fe}}^{3+}+·{{\mathrm{O}}_2}^{-}\to {\mathrm{Fe}}^{2+}+{{\mathrm{O}}_2}^{-}$.
Reaction 2: ${\mathrm{Fe}}^{2+}+{\mathrm{H}}_2{\mathrm{O}}_2\to {\mathrm{Fe}}^{3+}+·\mathrm{OH}+\mathrm{OH}$.

Show that reactions 1 and 2 are redox equations by writing the oxidation half-equation and the reduction half-equation for each.