EASY
Earn 100

State the converse of angle bisector theorem.

Important Questions on Triangles

MEDIUM
In ABCAD is the bisector of A intersects BC¯ in DBD=_____
MEDIUM
Let P Q R be an acute-angled triangle in which P Q<Q R . From the vertex Q draw the altitude QQ1 the angle bisector QQ2 and the median QQ3, with Q1,Q2,Q3 lying on P R. Then,
MEDIUM
In a triangle ABC,BAC=90°;AD is the altitude from A on to BC. Draw DE perpendicular to AC and DF perpendicular to AB. Suppose AB=15 and BC=25. Then the length of EF is
 
MEDIUM
The x-coordinate of the incentre of the triangle that has the coordinates of midpoints of its sides as 0,1, 1,1 and 1,0 is
HARD
If the line 3x+4y-24=0 intersects the x-axis at the point A and the y-axis at the point B, then the incentre of the triangle OAB, where O is the origin, is:
MEDIUM
D and E are the points on sides BC and AC, respectively of ABC. AD and BE intersect each other at T. If ATTD=5  and BTET=7  , then CD : BD =
EASY
Consider a Δ PQR in which the relation QR2+PR2=5 PQ2 holds. Let G be the point of intersection of medians P M and Q N . Then,  QGM is always
HARD

Question Image

In ABC, it is given that BDDC=ABAC, B=70°, C=50°. Find BAD in degrees.

MEDIUM
If a,b,c are lengths of the sides BC, CA and AB respectively of ΔABC and H is any point in the plane of ABC such that aAH+bBH+cCH=0, then H is the
EASY
If P(0, 0), Q(1, 0) and R12, 32 are three given points, then the centre of the circle for which the lines PQ, QR and RP are the tangents is
EASY
In ABCABC=90° andBAC=60°. If bisector of BAC meets BC at D. Then BD:DC is
MEDIUM
The incentre of the triangle with vertices  (1, 3 ), (0, 0) and (2, 0) is:
EASY

In the given figure, AD is the bisector of BAC. If AB=10cm, AC=6cm and BC=12cm. Find BD.

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EASY

In PQR, the bisector of P intersects QR in M. If PQ=10, PR=12, QM=8 then QR= _____.

MEDIUM

In the given fig.AMBC and AN is the bisector of A. If B=65° and C=33°, then the value of MAN will be

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MEDIUM
If ABCD is a rectangle and P is a point inside it such that AP=33, BP=16, DP=63. Find CP.
EASY

Let a, b, c be the side-length of a triangle and l, m, n be the lengths of its medians. Put K=l+m+na+b+c Then, as a, b, c vary, K can assume every value in the interval

MEDIUM
The incentre of the triangle formed by the straight line having 3 as X-intercept and 4 as Y-intercept, together with the coordinate axes, is
HARD
The angle bisectors BD and CE of a ΔABC are divided by the incentre I in the ratios 3:2 and 2:1 respectively. Then, the ratio in which I divides the angle bisector through A is
MEDIUM

If all the 3 vertices of an isosceles right angle triangle be integral points and length of base is also an integer, then which of the point is never a rational point (A point P(x,y) is integral point if both `x` and `y` are integers and point is rational, if both `x` and `y` are rational).