Statement 1: In order to fully charge a capacitor $\mathrm{C}$ to a potential difference of $\mathrm{V}$, the energy supplied by the battery is ${\mathrm{CV}}^2$

Statement 2: The work done in moving a charge $\mathrm{q}=\left(\mathrm{CV}\right)$ through a potential difference $\mathrm{V}$ is $\mathrm{qV}$

In the circuit given below, the capacitor $C$ is charged by closing the switch $S_1$ and opening the switch $S_2$. After charging, the switch $S_1$ is opened and $S_2$ is closed, then the maximum current in the circuit

A capacitor of capacitance $C$ is connected in series with a resistance $R$ and $DC$ source of emf $E$ through a key. The capacitor starts charging when the key is closed. By the time the capacitor has been fully charged, what amount of energy is dissipated in the resistance $R?$

The potential differences that must be applied across the parallel and series combination of $3$ identical capacitors is such that the energy stored in them becomes the same. The ratio of potential difference in parallel to series combination is

In figure, charge on the capacitor is plotted against potential difference across the capacitor. The capacitance and energy stored in the capacitor are respectively.

A capacitor of capacitance $\mathrm{C}=900 \mathrm{pF}$ is charged fully by $100 \mathrm{V}$ battery $B$ as shown in figure (a). Then it is disconnected from the battery and connected to another uncharged capacitor of capacitance $C=900 \mathrm{pF}$ as shown in figure (b). The electrostatic energy stored by the system (b) is