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E M B I B E
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
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EASY
Earn 100
Suppose
f
(
x
)
is differentiable at
x
=
1
and
lim
h
→
0
1
h
f
1
+
h
=
5
, and
f
(
1
)
=
0
, then
f
′
1
equals
(a)
4
(b)
3
(c)
6
(d)
5
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Important Questions on Limits
MEDIUM
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
lim
x
→
1
-
π
-
2
sin
-
1
x
1
-
x
is equal to
MEDIUM
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
lim
x
→
π
2
cot
x
-
cos
x
π
-
2
x
3
equals
EASY
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
lim
x
→
0
∫
0
x
2
sin
t
d
t
x
2
=
EASY
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
If
f
x
=
x
-
sin
x
x
+
cos
2
x
,
then
lim
x
→
∞
f
(
x
)
is equal to
MEDIUM
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
lim
x
→
∞
x
+
x
+
x
-
x
is equal to
MEDIUM
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
lim
x
→
0
1
+
2
x
-
1
x
=
EASY
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
lim
x
→
∞
(
x
2
+
1
-
x
2
-
1
)=
MEDIUM
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
Let
a
>
0
be a real number. Then the limit
lim
x
→
2
a
x
+
a
3
-
x
-
a
2
+
a
a
3
-
x
-
a
x
2
is-
EASY
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
lim
x
→
0
(
27
+
x
)
1
3
-
3
9
-
(
27
+
x
)
2
3
equals
HARD
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
The limit
l
i
m
x
→
∞
x
2
∫
0
x
e
t
3
-
x
3
d
t
equals
MEDIUM
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
If
f
is differentiable at
x
=
1
,
then
lim
x
→
1
x
2
f
1
-
f
x
x
-
1
is
HARD
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
If
·
denote the greatest integer function then
lim
n
→
∞
x
+
2
x
+
…
.
+
n
x
n
2
is -
HARD
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
Let
f
:
R
→
R
be a positive increasing function with
lim
x
→
∞
f
(
3
x
)
f
x
=
1
. Then,
lim
x
→
∞
f
(
2
x
)
f
(
x
)
is equal to
EASY
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
lim
x
→
∞
3
x
3
+
2
x
2
-
7
x
+
9
4
x
3
+
9
x
-
2
is equal to
MEDIUM
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
lim
x
→
3
3
x
-
3
2
x
-
4
-
2
is equal to
HARD
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
Let
f
:
R
→
R
be a function such that
lim
x
→
∞
f
x
=
M
>
0
. Then which of the following is
false
?
MEDIUM
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
The value of the
lim
x
→
0
x
sin
x
6
/
x
2
is-
HARD
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
For each positive real number
λ
,
let
A
λ
be the set of all natural numbers
n
such that
|
sin
(
n
+
1
-
sin
n
)
|
<
λ
.
Let
A
λ
c
be the complement of
A
λ
in the set of all natural numbers. Then-
HARD
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
The value of the
lim
x
→
-
∞
4
x
2
-
x
+
2
x
is
EASY
Mathematics
>
Differential Calculus
>
Limits
>
Methods of Evaluation of Limits
l
i
m
x
→
π
4
c
o
t
3
x
-
t
a
n
x
c
o
s
x
+
π
4
is