The MO electronic configuration of $X_2$ can be represented as follows:

Following conclusion can be drawn:
(I) It is excited state electronic configuration of ${\mathrm{X}}_2$
(II) It is more stable state than the ground state of ${\mathrm{X}}_2$ molecule
III) Bond order of $X_2$ in excited state is one
IV) It is more likely to dissociate into two X-atoms in ground state than in excited state

Which of the above conclusions are correct from given MO diagrams?