The area under acceleration–time graph represents

The displacement time graph of a moving particle is shown in Fig. $6.92$. The instantaneous velocity of the particle is negative at the point

Fig. (i)  and $\left(\mathrm{ii}\right)$ show the displacement-time graph of two particles moving along $x$-axis. We can say that:

The displacement of a particle is given by $y=a+bt+c{t}^2-d{t}^4$. The initial velocity and acceleration are respectively

A particle is thrown vertically upwards. The graph between its speed $v$ and time $t$ is given by (neglecting for resistance) the figure [See Fig. ].

The velocity-time curve for a body projected vertically upward is