The binding energy of B 4 e 9 nucleus is 58 . 0 M e V while that of H 2 e 4 nucleus is 28 . 3 M e V . But B 4 e 9 is less stable than H 2 e 4 . Why?

The stability of nuclei is the factor of the binding energy per nucleon and not only the binding energy. From the given data, it is indicated that, The binding energy of Be 4 9 = 58 . 0 MeV and number of nucleons = 9 , so the binding energy per nucleon is 58 9 = 6 . 33 MeV . Similarity, the binding energy per nucleon for He 2 4 = 28 . 3 4 = 7 . 1 MeV As the helium has more binding energy per nucleon, it is more stable.

The binding energy of B 4 e 9 nucleus is 58 . 0 M e V while that of H 2 e 4 nucleus is 28 . 3 M e V . But B 4 e 9 is less stable than H 2 e 4 . Why?

The stability of nuclei is the factor of the binding energy per nucleon and not only the binding energy. From the given data, it is indicated that, The binding energy of Be 4 9 = 58 . 0 MeV and number of nucleons = 9 , so the binding energy per nucleon is 58 9 = 6 . 33 MeV . Similarity, the binding energy per nucleon for He 2 4 = 28 . 3 4 = 7 . 1 MeV As the helium has more binding energy per nucleon, it is more stable.