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The capacitance of a parallel plate capacitor is 12 μF. If the distance between its plates is reduced to half and the area of plates is doubled, then the capacitance of the capacitor will become

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Important Questions on Capacitance

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The radius of the circular plates of a parallel plate capacitor is R. Air is the dielectric medium between the plates. If the capacitance of the capacitor is equal to the capacitance of a sphere of the radius R, then the distance between the plates is
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The work done against electric forces in increasing the potential difference of a condenser from 20 V to 40 V is W. The work done in increasing its potential difference from 40 V to 50 V will be
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The magnitude of charge in steady-state on either of the plates of condenser C in the adjoining circuit is-

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The plate separation in a parallel plate condenser is d and plate area is A. It is charged to V volt battery is disconnected, then the work done in increasing the plate separation to 2 d will be,
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A capacitor of capacitance C1 is charged to potential V and the battery is disconnected. Now the capacitor is connected to an uncharged capacitor of capacitance C2 then what will be the common potential of the combination-
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If the charge on a body is increased by 2 μC, the energy stored in it increases by 21%. The original charge on the body in micro-coulombs is
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What fraction of the energy drawn from the charging battery is stored in a capacitor?
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The plates of a parallel plate condenser are pulled apart with a velocity v. If at any instant mutual distance of separation is d, then the magnitude of the time of rate of change of electrostatic energy of the capacity depends on d as follows: (potential difference between plates is kept constant)-