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The correct circuit for a pnp transistor amplifier in common emitter configuration :-

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Important Questions on Semiconductor Devices

EASY
A transistor is used as a common emitter amplifier with a load resistance of 2 kΩ. The input resistance is 150 Ω. Base current is changed by 20 μA which results in a change in collector current by 1.5 mA. The voltage gain of the amplifier is
EASY
For a transistor, αdc and βdc are the current ratios, then the value of  βdc-αdcαdc  βdc is
EASY
In a common-emitter transistor amplifier, the audio signal voltage across the collector is 3 V. The resistance of collector is 3 . If current gain is 100 and the base resistance is 2 , the voltage and power gain of the amplifier is
EASY
An unknown transistor needs to be identified as a npn or pnp type. A multimeter, with +ve and -ve terminals, is used to measure resistance between different terminals of transistor. If terminal 2 is the base of the transistor then which of the following is correct for a pnp transistor?
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In the figure, given that VBB supply can vary from 0 to 5.0 V, VCC=5 V, βdc=200, RB=100 , RC=1  and VBE=1.0 V. The minimum base current and the input voltage at which the transistor will go to saturation, will be, respectively:

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EASY
For a common emitter configuration, if α and β have their usual meanings, the correct relationship between α and β is:
MEDIUM
The current gain of a common emitter amplifier is 69. If the emitter current is 7.0 mA, collector current is :
EASY
An NPN transistor operates as a common emitter amplifier, with a power gain of  60 dB . The input circuit resistance is  100 Ω and the output load resistance is  10 kΩ . The common emitter current gain β is:
EASY
The input signal is given to a CE amplifier having a voltage gain of 150 is Vi=2cos15t+π3. The corresponding output signal will be:
MEDIUM
For common emitter transistor amplifier, the audio signal voltage across the collector resistance of 2 kΩ is 4 V. If the current amplification factor of the transistor is 100 and the base resistance is 1 kΩ then the input signal voltage is
HARD
A realistic graph depicting the variation of the reciprocal of input resistance in an input characteristics measurement in a common emitter transistor configuration is :
MEDIUM
In a common emitter configuration with suitable bias, it is given that RL is the load resistance and RBE is small-signal dynamic resistance (input side). Then, voltage gain, current gain and power gain are given, respectively, by: β is current gain, IB, IC and IE are respectively base, collector, and emitter currents.
EASY
The ratio (R) of output resistance r0, and the input resistance ri in measurements of input and output characteristics of a transistor is typically in the range :
MEDIUM

An n-p-n transistor has three leads A, B and C. Connecting B and C by moist fingers, A to the positive lead of an ammeter, and C to the negative lead of the ammeter, one finds large deflection. Then, A, B and C refer respectively to :

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A common emitter amplifier circuit, built using an NPN transistor, is shown in the figure. Its dc current gain is 250RC=1  and VCC=10 V . The minimum base current for VCE to reach saturation is

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MEDIUM

The transfer characteristic curve of a transistor, having input and output resistance 100 Ω and 100 kΩ respectively, is shown in the figure. The voltage and power gain, are respectively:
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MEDIUM
An NPN transistor is used in common emitter configuration as an amplifier with 1 kΩ load resistance. Signal voltage of 10 mV is applied across the base-emitter. This produces a 3 mA change in the collector current and 15 μA  change in the base current of the amplifier. The input resistance and voltage gain are:
EASY
In a common emitter amplifier circuit using an n-p-n transistor, the phase difference between the input and the output voltages will be:
MEDIUM
A NPN transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 Ω is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuit is 192 Ω , the voltage gain and the power gain of the amplifier will respectively be:
HARD
In the circuit shown in the figure, the input voltage Vi is 20 V, VBE=0 and VCE=0. The values of IB, IC and β are given by

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