The correct circuit for a pnp transistor amplifier in common emitter configuration :-

In the figure, given that $V_{BB}$ supply can vary from $0$ to $5.0 \mathrm{V}, V_{CC}=5 \mathrm{V}, {\beta }_{dc}=200,$ $R_B=100\mathrm{ }\mathrm{k\Omega },$ $R_C=1 \mathrm{k\Omega }$ and $V_{BE}=1.0 \mathrm{V.}$ The minimum base current and the input voltage at which the transistor will go to saturation, will be, respectively:

The transfer characteristic curve of a transistor, having input and output resistance $100 \mathrm{\Omega }$ and $100 \mathrm{k}\mathrm{\Omega }$ respectively, is shown in the figure. The voltage and power gain, are respectively:

The output characteristics of a transistor is shown in the figure. When ${\mathrm{V}}_{\mathrm{CE}}$ is $10\mathrm{V}$ and ${\mathrm{I}}_{\mathrm{C}}=4.0\mathrm{mA}$, then value of ${\mathrm{\beta }}_{\mathrm{ac}}$ is 

An n-p-n transistor has three leads A, B and C. Connecting B and C by moist fingers, A to the positive lead of an ammeter, and C to the negative lead of the ammeter, one finds large deflection. Then, A, B and C refer respectively to :