EASY

JEE Main/Advance

IMPORTANT

Earn 100

The electric field due to charged circular arc shown in following figure, at centre $O$ is

100% studentsanswered this correctly

Important Questions on Electric Charges and Fields

MEDIUM

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 15 - Electric Charges and Fields>Assignment Set-2>Q 8

If $λ = 1 μ C m^{- 1}$ , then electric field intensity at $O$ is

Question Image

EASY

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 15 - Electric Charges and Fields>Assignment Set-2>Q 9

A test charge $q_{0}$ is placed in the electric field of a source charge $Q .$ The test charge will not follow path of electric field line if

Question Image

EASY

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 15 - Electric Charges and Fields>Assignment Set-2>Q 10

The electric field in a region of space is spherically symmetric and radially outward. The flux of electric field through a sphere of radius

r

, centred at origin is

ϕ = k r^{4} .

Which of the following is the correct relation between electric field strength with radial distance

r

from origin?

EASY

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 15 - Electric Charges and Fields>Assignment Set-2>Q 11

If electric field in a region is given by

\vec{E} = \frac{E_{0} . x}{l} \hat{i} + \frac{E_{0} . y^{2}}{l^{2}} \hat{j} + \frac{E_{0} . z^{3}}{l^{3}} \hat{k}

where

E_{0} = 5 \times 10^{3} \frac{N}{C}, l = 2 cm .

then electric flux passing through the plane

x = 2 cm .

The plane is a square of side

2 cm .

EASY

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 15 - Electric Charges and Fields>Assignment Set-2>Q 12

If electric field in a region is given as

\vec{E} = \frac{E_{0} . x}{l} \hat{i} + \frac{E_{0} . y^{2}}{l^{2}} \hat{j} + \frac{E_{0} . z^{3}}{l^{3}} \hat{k} (E_{0} = 5 \times 10^{3} \frac{N}{C}, l = 2 cm)

, then calculate the flux of electric field passing through a rectangular plane

(2 cm \times 1 cm)

y = 2 cm

EASY

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 15 - Electric Charges and Fields>Assignment Set-2>Q 13

If electric field in a region is given by

\vec{E} = \frac{E_{0} . x}{l} \hat{i} + \frac{E_{0} . y^{2}}{l^{2}} \hat{j} + \frac{E_{0} . z^{3}}{l^{3}} \hat{k}

where

E_{0} = 5 \times 10^{3} \frac{N}{C}, l = 2 cm .

then electric flux passing through the plane

x = 2 cm .

The plane is a square of side

2 cm .

The flux passing through a triangular plane (Area

2 {cm}^{2}

) at

z = 0

will be

MEDIUM

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 15 - Electric Charges and Fields>Assignment Set-2>Q 14

The electric flux through ring shown in figure is

Question Image

MEDIUM

JEE Main/Advance

IMPORTANT

Gamma Question Bank for Engineering Physics>Chapter 15 - Electric Charges and Fields>Assignment Set-2>Q 15

A ball of radius

R

carries a positive charge whose volume charge density depends only on the distance

r

from the ball's centre as

ρ = ρ_{0} [1 - \frac{r}{R}]

where

ρ_{0}

is a constant.
The electric field at distance

r > R

will be

The electric field due to charged circular arc shown in following figure, at centre O is

Important Questions on Electric Charges and Fields

Learn and Prepare for any exam you want !

The electric field due to charged circular arc shown in following figure, at centre $O$ is