EASY
9th ICSE
IMPORTANT
Earn 100

The electronic configuration of fluoride ion is the same as that of a neon atom. What is the difference between the two ?

Important Questions on Atomic Structure and Chemical Bonding

EASY
9th ICSE
IMPORTANT
Concise Chemistry Class 9>Chapter 4 - Atomic Structure and Chemical Bonding>EXERCISE 4(D)>Q 12
What do you understand by the redox reactions?
EASY
9th ICSE
IMPORTANT
Concise Chemistry Class 9>Chapter 4 - Atomic Structure and Chemical Bonding>EXERCISE 4(D)>Q 12
Explain oxidation and reduction in terms of loss or gain of electrons.
EASY
9th ICSE
IMPORTANT
Concise Chemistry Class 9>Chapter 4 - Atomic Structure and Chemical Bonding>EXERCISE 4(D)>Q 13

Potassium (At. No. 19) and chlorine (At. No. 17) form a compound. Explain the formation of the compound on the basis of :

Oxidation.

EASY
9th ICSE
IMPORTANT
Concise Chemistry Class 9>Chapter 4 - Atomic Structure and Chemical Bonding>EXERCISE 4(D)>Q 13

Potassium (At. No. 19) and chlorine (At. No. 17) form a compound. Explain the formation of the compound on the basis of reduction.

EASY
9th ICSE
IMPORTANT
Concise Chemistry Class 9>Chapter 4 - Atomic Structure and Chemical Bonding>EXERCISE 4(D)>Q 13

Potassium (At. No. 19) and chlorine (At. No. 17) form a compound. Explain the formation of the compound on the basis of:

Oxidising agent.

EASY
9th ICSE
IMPORTANT
Concise Chemistry Class 9>Chapter 4 - Atomic Structure and Chemical Bonding>EXERCISE 4(D)>Q 13

Potassium (At. No. 19) and chlorine (At. No. 17) form a compound. Explain the formation of the compound on the basis of:

Reducing agent.

EASY
9th ICSE
IMPORTANT
Concise Chemistry Class 9>Chapter 4 - Atomic Structure and Chemical Bonding>EXERCISE 4(E)>Q 1
Define covalent (molecular) bond.
EASY
9th ICSE
IMPORTANT
Concise Chemistry Class 9>Chapter 4 - Atomic Structure and Chemical Bonding>EXERCISE 4(E)>Q 1

Give an example of covalent bond formed by:

Similar atoms.