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The equation of motion for pendulum is

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Important Questions on Oscillations

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The system that returns to equilibrium as quickly as possible without oscillating is
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The amplitude of a mass-spring system, which is executing simple harmonic motion decreases with time. If mass =500 g, Decay constant =20 g s-1 then how much time is required for the amplitude of the system to drop to half of its initial value? ln2=0.693
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When a simple pendulum is moved from the Earth's surface to deep mine, the period of oscillation
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Two simple pendulums with time periods T0 and T1 start oscillating in the same direction at the same time. If T0>T1 and the phase difference between them is π3 when the faster pendulum has completed one oscillation, then T1 is
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The displacement of a damped harmonic oscillator is given by xt=e-0.1tcos10πt+φ. Here t is in seconds. The time taken for its amplitude of vibration to drop to half of its initial value is close to:
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The phenomenon that occurs when the frequency of forced vibrations on an object matches the natural frequency of that object, and produces a dramatic increase in amplitude is called
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T0 is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to 116 times of its initial value, the modified time period is
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The path length of oscillation of simple pendulum of length 1 m is 16 cm. Its maximum velocity is g=πs-2

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The bob of simple pendulum is a spherical hollow ball filled with water. A plugged hole near the bottom of the oscillating bob get suddenly unplugged. During observation, till water is coming out, the time period of oscillation would
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A block of mass 1 kg attached to a spring is made to oscillate with an initial amplitude of 12 cm. After 2 minutes the amplitude decreases to 6 cm. Determine the value of the damping constant for this motion. (take ln2=0.693 )
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In case of a forced vibration, the resonance wave becomes very sharp when the:
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The amplitude of a simple pendulum, oscillating in air with a small spherical bob, decreases from 10 cm to 8 cm in 40 seconds. Assuming that Stokes law is valid, and ratio of the coefficient of viscosity of air to that of carbon dioxide is 1.3, the time in which amplitude of this pendulum will reduce from 10 cm to 5 cm in carbondioxide will be close to (ln 5 = 1.601, ln 2 = 0.693).

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A simple pendulum is oscillating in a lift. If the lift starts moving upwards with uniform acceleration, the period _____.
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My friend has a Banjo clock. It has a pendulum. For every 1.0 sec the pendulum performs one full swing. If an object at the end of the string weighs 10.0 N, what is the length of the pendulum?
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Time period of a simple pendulum in a stationary lift is T. If the lift accelerates with g6 vertically upwards then the time period will be
(Where g= acceleration due to gravity)
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In an experiment to determine the period of a simple pendulum of length 1 m, it is attached to different spherical bobs of radii r1 and r2 . The two spherical bobs have uniform mass distribution. If the relative difference in the periods, is found to be 5×10-4 s, the difference in radii, r1-r2 is best-given by
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A tunnel is dug along the diameter of the earth. A mass m is dropped into it. How much time does it take to cross the earth?
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Time period of a simple pendulum is T inside a lift when the lift is stationary. If the lift moves upwards with an acceleration g2, the time period of pendulum will be :
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In an experiment to determine the gravitational acceleration g of a place with the help of a simple pendulum, the measured time period squared is plotted against the string length of the pendulum in the figure. What is the value of g at the place?
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A block of mass 0.1 kg is connected to an elastic spring of spring constant 640 N m-1 and oscillates in a damping medium of damping constant 10-2 kg s-1 . The system dissipates its energy gradually. The time taken for its mechanical energy of vibration to drop to half of its initial value, is closest to-