The figure shows three circuits with identical batteries, inductors and resistances. Rank the circuits according to the currents through the battery just after the switch is closed, greatest first. 
(Given that the inductance of each inductor is $L$ and the resistance of each resistor is $R$ and the emf of each battery is $E$.)

As shown in the figure, a battery of emf $\in$ is connected to an inductor $L$ and resistance $R$ in series. The switch is closed at $t=0.$ The total charge that flows from the battery, between $t=0$ and $t=\tau$ ( $\tau$ is the time constant of the circuit) is:

When a $\mathrm{DC}$ voltage is applied at the two ends of a circuit kept in a closed box, it is observed that the current gradually increases from zero to a certain value and then remains constant. What do you think that the circuit contains?

In the circuit shown below, all the inductors (assumed ideal) and resistors are identical. The current through the resistance on the right is $I$ after the key $K$ has been switched on for along time. The currents through the three resistors (in order, from left to right) immediately after the key is switched off are-

A $20$ $\text{H}$ inductor coil is connected to a $10$ $\mathrm{\Omega }$ resistance in series as shown in figure. The time at which rate of dissipation of energy (Joule's heat) across resistance is equal to the rate at which magnetic energy is stored in the inductor, is:

The current $\left(\mathrm{i}\right)$ at time $t=0$ and $t=\infty$ respectively for the given circuit is :

In the figure shown, a circuit contains two identical resistors with resistance $R=5\Omega$ and an inductance with $L=2mH.$ An ideal battery of $15V$ is connected in the circuit. What will be the current through the battery long after the switch is closed?

The figure shows a circuit that contains four identical resistors with resistance $R=2.0 \mathrm{\Omega },$ two identical inductors with inductance $L=2.0 \mathrm{mH}$ and an ideal battery with E.M.F. $E=9 \mathrm{V}.$ The current $i$ just after the switch $S$ is closed will be:

A part of a complete circuit is shown in the figure. At some instant, the value of current I is $1\mathrm{A}$ and it is decreasing at a rate of ${10}^2{\mathrm{As}}^{-1}$. The value of the potential difference ${\mathrm{V}}_{\mathrm{p}}-{\mathrm{V}}_{\mathrm{Q}},$ (in volts) at that instant is-

For the given circuit the current $i$ through the battery when the key in closed and the steady state has been reached is

Figure shows a circuit contains three identical resistors with resistance $R=9.0 \mathrm{\Omega }$ each, two identical inductors with inductance $L=2.0\hspace{0.17em}\hspace{0.17em}\mathrm{mH}$ each, and an ideal battery with emf $\epsilon = 18 \mathrm{V}$. The current $i$ through the battery just after the switch closed is:

An inductor $(L=0.03\mathrm{\hspace{0.17em}}\mathrm{H})$ and a resistor $(R=0.15 \mathrm{\hspace{0.17em}}\mathrm{k\Omega })$ are connected in series to a battery of $15\mathrm{\hspace{0.17em}}\mathrm{V}$ E.M.F. in a circuit shown below. The key $K_1$ has been kept closed for a long time. Then at $t=0$, $K_1$ is opened and key $K_2$ is closed simultaneously. At $t=1\mathrm{\hspace{0.17em}}\mathrm{ms}$ , the current in the circuit will be : $\left(\text{Take}, e^5\approx 150\right)$