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The first law of thermodynamics is a special case of,

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Important Questions on Thermodynamics

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JEE Main
IMPORTANT
An ideal gas undergoes the cyclic process abca  as shown in the figure. The internal energy change of the gas along the path ca  is  180 J . The gas absorb 250 J of heat along the path ab  and also absorbs  60 J  of heat along the path bc . Find the work done by the gas along the path abc

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A given quantity of gas is taken from the state A to the state C reversibly by two paths, AC directly and A BC as shown in the figure below:

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During the process AC, work done by the gas is 100 J and heat absorbed is 120 J. If during the process ABC, the work done by the gas is 80 J, the heat absorbed is

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JEE Main
IMPORTANT
Four moles of hydrogen, two moles of helium and one mole of water vapor form an ideal gas mixture. What is the molar specific heat at constant pressure of mixture?
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JEE Main
IMPORTANT
For a diatomic gas, change in internal energies per unit change in temperature for constant pressure and volume are U1 and U2, respectively. Then U1:U2 is
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JEE Main
IMPORTANT

Find the work done by the gas in the process shown in figure.

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JEE Main
IMPORTANT
An ideal gas is taken through a cyclic thermodynamic process through four steps. The amount of heat involved in these steps are Q1=5960 J,Q2=5585 J,Q3=2980 J and Q4=3645 J, respectively. The corresponding work involved are W1=2200 J, W2=825 J, W3=1100 J and W4, respectively. The value of W4 is
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IMPORTANT

A gas at state A changes to state B through path I and II shown in figure. The change in internal energy is ΔU1 and ΔU2, respectively. Then

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JEE Main
IMPORTANT
If γ be the ratio of specific heats of a perfect gas, the number of degrees of freedom of a molecule of the gas is