The logical equivalent statement of $p\leftrightarrow q$ is

Let $p,q,r$ be three logical statements. Consider the compound statements
$S_1:\left(\left(~p\right)\vee q\right)\vee \left(\left(~p\right)\vee r\right)$ and $S_2:p\to \left(q\vee r\right)$
Then, which of the following is NOT true?

If the truth value of the Boolean expression $\left(\right(p\vee q)\wedge (q\to r)\wedge (~r\left)\right)\to (p\wedge q)$ is false, then the truth values of the statements $p, q, r$ respectively can be: