The $\mathrm{pKa}$ value of four halo phenols is given below:

Consider the following statements regarding $\mathrm{pKa}$ value:

(1) $\mathrm{F},\mathrm{Cl},\mathrm{Br}$ and $\mathrm{I}$ atoms have both $-\mathrm{I}$ and $+\mathrm{R}$ effects

(2) In case of $\mathrm{p}$-chloro, $\mathrm{p}$-bromo, and $\mathrm{p}$-iodophenoxide ions, $\mathrm{Cl},\mathrm{Br}$ and $\mathrm{I}$ acts as $\mathrm{d}-\mathrm{\pi }$ accept (- $\mathrm{R}$ effect)

(3) Due to $\mathrm{d}-\mathrm{\pi }$ acceptor nature of halogen atom, the negative charge on oxygen of phenoxide ion gets delocalised and hence $-\mathrm{R}$ effect predominates.

(4) The $\mathrm{d}-\mathrm{\pi }$ accepting ability order is as $\mathrm{I}>\mathrm{Br}>\mathrm{Cl}$. Hence $\mathrm{p}$-iodophenol is most acidic.

Of the these the correct statements are :