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The potential energy of an electron in He+ ion is -12.09 eV. In which excited state is the electron is present?

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Important Questions on Atomic Structure

MEDIUM

The ionization energy of gaseous Na atoms is 495.5 kJ mol-1. The lowest possible frequency of light that ionizes a sodium atom is 

(h=6.626×10-34 Js, NA=6.022×1023 mol-1)

EASY
Which of the following is the energy of a possible excited state of hydrogen?
MEDIUM
The energy of an electron in first Bohr's orbit of H atom is 13.6eV. The energy value of electron in the first excited state of Li 2+ is :
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The ratio of the shortest wavelength of two spectral series of hydrogen spectrum is found to be about 9. The spectral series are:
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The radius of the second Bohr orbit for hydrogen atom is

(Planck's constant, (h)=6.6262×1034Js; mass of electron =9.1091×10-31kg; charge of electron =1.60210×10-19C; permittivity of vacuum, (0)=8.854185×10-12kg-1m-3A2)
EASY
Which of the following series of transitions in the spectrum of hydrogen atom falls in visible region?
MEDIUM
If the shortest wavelength in Lyman series of hydrogen atom is A, then the longest wavelength in Paschen series of He+ is
HARD
Consider the Bohr's model of a one-electron atom where the electron moves around the nucleus. In the following List-I contains some quantities for the nth orbit of the atom and List-II contains options showing how they depend on n .
 
List - I List - II
(I) Radius of the nth orbit P n-2
(II) Angular momentum of the electron in the nth orbit Q n-1
(III) Kinetic energy of the electron in the nth orbit R n0
(IV) Potential energy of the electron in the nth orbit S n1
  T n2
  U n1/2

Which of the following options has the correct combination considering List-I and List-II?
EASY
The radii of the first Bohr orbit of H rH, He+rHe+ and Li2+rLi2+ are in the order
EASY
If the radius of the hydrogen atom is 53 pm, the radius of the He+ ion is closest to:
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The radius of the second Bohr orbit, in terms of the Bohr radius, a0, in Li2+ is:
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If the de Broglie wavelength of the electron in nth Bohr orbit in a hydrogenic atom is equal to 1.5 πa0 (a0 is Bohr radius), then the value of nz is:
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For the Balmer series, in the spectrum of H atom, v-=RH1n12-1n22, the correct statements among I to IV are,
I As wavelength decreases, the lines in the series converge.
II The integer n1 is equal to 2.
III The lines of the longest wavelength correspond to n2=3.
IV The ionization energy of hydrogen can be calculated from the wave number of these lines.
MEDIUM

For any given series of spectral lines of atomic hydrogen, let  Δv-=v-max-v-min  be the difference in maximum and minimum wave number in cm-1

The ratio Δv-Lyman/Δv-Balmar is

MEDIUM
Consider the Bohr's model of a one-electron atom where the electron moves around the nucleus. In the following List-I contains some quantities for the nth orbit of the atom and List-II contains options showing how they depend on n .
 
List - I List - II
(I) Radius of the nth orbit P n-2
(II) Angular momentum of the electron in the nth orbit Q n-1
(III) Kinetic energy of the electron in the nth orbit R n0
(IV) Potential energy of the electron in the nth orbit S n1
  T n2
  U n1/2

Which of the following options has the correct combination considering List-I and List-II?
MEDIUM
The shortest wavelength of H atom in the Lyman series is λ1. The longest wavelength in the Balmer series of He+ is :
MEDIUM

The difference between the radii of 3rd and 4th  orbits of Li2+ is ΔR1. The difference between the radii of 3rd and 4th  orbits of He+ is ΔR2. Ratio of  ΔR1:ΔR2 is :

EASY
The electron in the hydrogen atom undergoes transition from higher orbitals to orbital of radius 211.6 pm. This transition is associated with
HARD
Energy of an electron is given by  E=-2.178×10-18Z2n2 J. Wavelength of light required to excite an electron in a hydrogen atom from level n=1 to n=2 will be :
h=6.62×10-34 Js and c=3.0×108 ms-1
MEDIUM
The ground state energy of a hydrogen atom is -13.6 eV. The energy of second excited state of He+ ion in eV is: