EASY

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The radiation with maximum frequency is

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Important Questions on Structure of Atom

MEDIUM

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

The first member of the Balmer series of hydrogen atom has a wavelength of

6561 \overset{\circ}{A}

. The wavelength of the second member of the Balmer series (in nm) is_____________

EASY

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

The frequency for a series limit of Balmer and Paschen series respectively are

f_{1}

and

f_{3}

. If the frequency of the first line of Balmer series is

f_{2}

then the relation between

f_{1}, f_{2}

and

f_{3}

MEDIUM

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

If the shortest wavelength in Lyman series of hydrogen atom is

A

, then the longest wavelength in Paschen series of

{He}^{+}

MEDIUM

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

The ratio of the shortest wavelength of two spectral series of hydrogen spectrum is found to be about

9

. The spectral series are:

EASY

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

The value of Planck's constant is

6 .63 \times 10^{- 34} Js

and the velocity of light is

3 .0 \times 10^{8} {ms}^{- 1}

. Which value is the closest to the wavelength in nanometers of a quantum of light, with a frequency of

8 \times 10^{15} s^{- 1}

MEDIUM

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

For any given series of spectral lines of atomic hydrogen, let $Δ \bar{v} = {\bar{v}}_{m a x} - {\bar{v}}_{m i n}$ be the difference in maximum and minimum wave number in $c m^{- 1}$ .

The ratio $Δ {\bar{v}}_{L y m a n} / Δ {\bar{v}}_{B a l m a r}$ is

MEDIUM

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

According to Bohr's theory, the time averaged magnetic field at the centre (i.e., nucleus) of a hydrogen atom due to the motion of electrons in the

n^{t h}

orbit is proportional to: (

n =

principal quantum number)

HARD

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

Radiation, with wavelength

6561 Å

falls on a metal surface to produce photoelectrons. The electrons are made to enter a uniform magnetic field of

3 \times 10^{- 4} T

. If the radius of the largest circular path followed by the electrons is

10 m m

, the work function of the metal is close to:

EASY

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

Given the value of Rydberg constant is

10^{7} m^{- 1}

, the wave number of the last line of the Balmer series in hydrogen spectrum will be:

MEDIUM

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

Which of the graphs shown below does not represent the relationship between incident light and the electron ejected from metal surface?

EASY

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

Calculate the energy in corresponding to light of wavelength

45 n m :

(Planck’s constant

h = 6.63 \times 10^{- 34} J s : s p e e d o f l i g h t c = 3 \times 10^{8} m s^{- 1})

EASY

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

A particular station of All India Radio, New Delhi, broadcasts on a frequency of

1, 368 kHz

(kilo Hertz). The wavelength of the electromagnetic radiation emitted by the transmitter is [speed of light,

c = 3.0 \times 10^{8} {ms}^{- 1}

]

EASY

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

When the electron in hydrogen atom jumps from fourth Bohr orbit to second Bohr orbit, one gets the

MEDIUM

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

Taking the wavelength of first Balmer line in hydrogen spectrum

(n = 3

n = 2)

660 n m

, the wavelength of the

2^{n d}

Balmer line

(n = 4

n = 2)

will be :

EASY

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

The time period of revolution of electron in its ground state orbit in a hydrogen atom is

1.6 \times 10^{- 16} s .

The frequency of revolution of the electron in its first excited state (in

s^{- 1}

) is:

MEDIUM

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

For which one of the following, Bohr model is not valid?

HARD

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

The work function of sodium metal is

4.41 \times 10^{- 19} J .

If photons of wavelength

300 nm

are incident on the metal, the kinetic energy of the ejected electrons will be

(h = 6.63 \times 10^{- 34} J s; c = 3 \times 10^{8} m s^{- 1})

__________

\times 10^{- 21} J

EASY

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

In Balmer series for hydrogen atom, find the energy of photon corresponding to longest wavelength.

EASY

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

Which mathematical statement did not prove false?

MEDIUM

Chemistry>Physical Chemistry>Structure of Atom>Dual Behaviour of Electromagnetic Radiation

Electromagnetic radiation of wavelength

663 nm

is just sufficient to ionise the atom of metal

A

. The ionization energy of metal

A

kJ {mol}^{- 1}

is ___. (Rounded-off to the nearest integer)

[h = 6.63 \times 10^{- 34} Js, c = 3.00 \times 10^{8} {ms}^{- 1}, N_{A} = 6.02 \times 10^{23} {mol}^{- 1}]

The radiation with maximum frequency is

Important Questions on Structure of Atom

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