The reaction of chloroform with alcoholic $\mathrm{KOH}$ and $\mathrm{p}$-toluidine forms:

In the chemical reaction, 

${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NH}}_2+{\mathrm{CHCl}}_3+3\mathrm{KOH}⟶\left(\mathrm{A}\right)+\left(\mathrm{B}\right)+3{\mathrm{H}}_2\mathrm{O}$ the compounds $\left(\mathrm{A}\right)$ and $\left(\mathrm{B}\right)$ are respectively:

In the chemical reactions the compounds $\text{'}\mathrm{A}\text{'}$ and $\text{'}\mathrm{B}\text{'}$ respectively are:

In below reactions, the compounds $\mathrm{A}$ and $\mathrm{B}$ are respectively: 

In the reaction 

the product $\mathrm{E}$ is: