The reaction of zinc with sulphuric acid is represented by the equation: Zn + H 2 SO 4 → ZnSO 4 + H 2 The net ionic equation can be represented by two half equations. Write these equations.

The chemical equation representing the reaction of zinc with sulphuric acid is: Zn s + H 2 SO 4 aq → ZnSO 4 aq + H 2 g Net ionic equation: Zn s + 2 H + aq → Zn 2 + aq + H 2 g

The reaction of zinc with sulphuric acid is represented by the equation: Zn + H 2 SO 4 → ZnSO 4 + H 2 The net ionic equation can be represented by two half equations. Write these equations.

The chemical equation representing the reaction of zinc with sulphuric acid is: Zn s + H 2 SO 4 aq → ZnSO 4 aq + H 2 g Net ionic equation: Zn s + 2 H + aq → Zn 2 + aq + H 2 g

The reaction of zinc with sulphuric acid is represented by the equation: Zn + H 2 SO 4 → ZnSO 4 + H 2 Explain why this is redox reaction.

Zn + H 2 SO 4 → ZnSO 4 + H 2 This is an example of a displacement reaction. The reaction can also be classified as a redox reaction, since oxidation and reduction take place. Oxidation : Zinc metal loses its two electrons and forms zinc cation. Zn - 2 e - → Zn 2 + Reduction : The hydrogen ion of the acid gains those two electrons and forms hydrogen gas. 2 H + + 2 e - → H 2

Identify the substance that is oxidised and reduced in the following reaction- MnO 2 + 4 HCl → MnCl 2 + 2 H 2 O + Cl 2

In the given reaction, MnO 2 is losing oxygen to form MnCl 2 and HCl is losing hydrogen to form Cl 2 . MnO 2 Manganese dioxide + 4 HCl Hydrochloric acid → MnCl 2 Manganese dichloride + 2 H 2 O Water + Cl 2 Chlorine Therefore, we can conclude- Substance that is oxidised and which is acting as a reducing agent is HCl . Substance that is reduced and which is acting as an oxidising agent is MnO 2 .