The schematic symbol of light emitting diode is (LED)

Take the breakdown voltage of the zener diode used in the given circuit as $6 \mathrm{V}$. For the input voltage shown in the figure below, the time variation of the output voltage is: (Graphs drawn are schematic and not to the scale)

The $6 \mathrm{V}$ Zener diode shown in the figure has negligible resistance and a knee current of $5 \mathrm{mA}$. The minimum value of $\mathrm{R}\mathrm{ }\left(\mathrm{in}\mathrm{ }\mathrm{\Omega }\right)$ so that the voltage across it does not fall below $6 \mathrm{V}$ is

Two Zener diodes ($A$ and $B$) having breakdown voltages of $6 \mathrm{V}$ and  $4 \mathrm{V}$ respectively, are connected as shown in the circuit below. The output voltage $V_0$ variation with input voltage linearly increasing with time, is given by ($V_{input} = 0 \mathrm{V} \text{at} t = 0$)

In case of a p-n junction diode at high value of reverse bias, the current rises sharply. The value of reverse bias is known as

The value of the resistor, $R_S$, needed in the DC voltage regulator circuit shown here, equals:

Two $p$ - $n$ photodiodes are fabricated from semiconductors with band gap of $2.8\mathrm{eV}$ and $2.6\mathrm{eV},$ respectively.

Choose the correct statement from the following.

In the circuit shown, what will be the current through the $6 \mathrm{V}$ zener?

What will be the current flowing through the $6 \mathrm{k\Omega }$ resistor in the circuit shown, where the breakdown voltage of the Zener is $6 \mathrm{V}?$