Hydrogen ( 1 H 1 ), Deuterium ( 1 H 2 ), singly ionised Helium ( 2 He 4 ) + and doubly ionised lithium ( 3 Li 6 ) ++ all have one electron around the nucleus. Consider an electron transition from n = 2 to n = 1 . If the wave lengths of emitted radiation are λ 1 , λ 2 , λ 3 and λ 4 respectively then approximately which one of the following is correct ?

4 λ 1 = 2 λ 2 = 2 λ 3 = λ 4

λ 1 = 2 λ 2 = 3 λ 3 = 4 λ 4

HARD

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The shortest wavelength of the Brackett series of a hydrogen like atom (atomic number $= Z$ ) is the same as the shortest wavelength of the Balmer series of hydrogen atom. The value of $Z$ is

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Important Questions on Atomic Physics

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

When the electron in hydrogen atom jumps from fourth Bohr orbit to second Bohr orbit, one gets the

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

The first member of the Balmer series of hydrogen atom has a wavelength of

6561 \overset{\circ}{A}

. The wavelength of the second member of the Balmer series (in nm) is_____________

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

In Balmer series, wavelength of first line is

λ_{1}

and in Brackett series wavelength of first line is

λ_{2}

then

\frac{λ_{1}}{λ_{2}}

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

Given the value of Rydberg constant is

10^{7} m^{- 1}

, the wave number of the last line of the Balmer series in hydrogen spectrum will be:

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

The ratio of wavelengths of the last line of the Balmer series and the last line of the Lyman series is_____.

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

The shortest wavelength of Paschen series in hydrogen spectrum is

8182 \overset{\circ}{A}

. The first member of the Paschen series is nearly

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

Taking the wavelength of first Balmer line in hydrogen spectrum

(n = 3

n = 2)

660 n m

, the wavelength of the

2^{n d}

Balmer line

(n = 4

n = 2)

will be :

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

Which of the series of hydrogen atom spectrum lies in the visible region of electromagnetic spectrum?

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is:

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

If the series limit frequency of the Lyman series is

V_{L},

then the series limit frequency of the Pfund series is:

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

The series corresponding to lowest wavelength transition in

H

- atom.

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

In Balmer series for hydrogen atom, find the energy of photon corresponding to longest wavelength.

HARD

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

In hydrogen spectrum,

L_{α}

line arises due to transition of electron from the orbit

n = 3

to the orbit

n = 2

. In the spectrum of singly ionized helium, there is a line having the same wavelength as that of the

L_{α}

line of hydrogen. This is due to the transition of the electron from the orbit ______ to ________

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

The energy required to ionise a hydrogen like ion in its ground state is

9

Rydbergs. What is the wavelength of the radiation emitted when the electron in this ion jumps from the second excited state to the ground state?

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

Hydrogen atom in its ground state is excited by a monochromatic light of energy

13.06 eV

. The longest wavelength among the spectral lines is (Ionization energy of hydrogen atom is

13.6 eV

)

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

According to Bohr atom model, in which of the following transitions will the frequency be maximum?

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

The shortest wave lengths of Paschen, Balmer and Lyman series are in the ratio

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

An electron from various excited states of hydrogen atom emit radiation to come to the ground state. Let

λ_{n}, λ_{g}

be the de Broglie wavelength of the electron in the

n^{t h}

state and the ground state respectively. Let

\land_{n}

be the wavelength of the emitted photon in the transition from the

n^{t h}

state to the ground state. For large n, (A, B are constants)

EASY

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

The frequency for a series limit of Balmer and Paschen series respectively are

f_{1}

and

f_{3}

. If the frequency of the first line of Balmer series is

f_{2}

then the relation between

f_{1}, f_{2}

and

f_{3}

MEDIUM

Physics>Modern Physics>Atomic Physics>Emission and Absorption Spectrum

Hydrogen (₁H¹), Deuterium (₁H²), singly ionised Helium (₂He⁴)⁺ and doubly ionised lithium (₃Li⁶)⁺⁺ all have one electron around the nucleus. Consider an electron transition from

n = 2

n = 1

. If the wave lengths of emitted radiation are

λ_{1}, λ_{2}, λ_{3}

and

λ_{4}

respectively then approximately which one of the following is correct ?

The shortest wavelength of the Brackett series of a hydrogen like atom (atomic number =Z ) is the same as the shortest wavelength of the Balmer series of hydrogen atom. The value of Z is

Important Questions on Atomic Physics

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The shortest wavelength of the Brackett series of a hydrogen like atom (atomic number $= Z$ ) is the same as the shortest wavelength of the Balmer series of hydrogen atom. The value of $Z$ is