The solubility of aldehydes and ketones decreases rapidly with increasing length of the alkyl chain. Explain.

How would you account for:

Boiling points of aldehydes are lower than alcohols.

Arrange the following compounds in increasing order of their boiling points: ${\mathrm{CH}}_3-\mathrm{CHO}, {\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}, {\mathrm{CH}}_3-\mathrm{O}-{\mathrm{CH}}_3, {\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_3$

Given below are two statements:
Statement $\mathrm{I}$: The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole - dipole interactions.
Statement $\mathrm{II}$: The boiling points of aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of $\mathrm{H}$-bonding.

In the light of the above statements, choose the most appropriate answer from the options given below :

Select the option in which all the carbonyl compounds are miscible with water in all proportions?

Decreasing order of boiling point of $\mathrm{I}$ to $\mathrm{IV}$ follows:

Decreasing order of boiling point of $\mathrm{I}$ to $\mathrm{IV}$ follow:

The smell of bitter almond is given by the compound. 

Arrange the following compounds in the increasing order of their boiling points. 

Dimethyl ether, ethyl alcohol, propane, acetaldehyde.

Which of the compound is soluble in ${\mathrm{H}}_{\mathrm{2}}\mathrm{O}$?