EASY
Earn 100

The standard heat of combustion of a hydrocarbon compound is an/a-

75% studentsanswered this correctly

Important Questions on Use mathematical representations to support the claim that atoms, and therefore mass, are conserved during a chemical reaction.

HARD

The standard enthalpies of formation of CO2(g) ,H2Ol and glucose (s) at 2 5 o C are  - 400 kJ / mol , - 300 kJ / mol and - 1300 kJ / mol , respectively. The standard enthalpy combustion per gram of glucose at 2 5 o C is 

(ΔHf0=1300kJmol1 for Glucose)

HARD
For the reaction N2+3X22NX3 where X=F, Cl (the average bond energies are F-F=155 kJ mol-1, N-F=272 kJ mol-1, Cl-Cl=242 kJ mol-1, N-Cl=200 kJ mol-1 and NN=941 kJ mol-1), the heats of reaction of NF3 and NCl3 in kJ mol-1, respectively, are closest to
HARD
Given:

Cgraphite+O2gCO2g ;ΔrHo=393.5 kJ mol1

H2g+12O2gH2Ol;ΔrHo=-285.8 kJ mol-1

CO2g+2H2OlCH4g+2O2g;ΔrHo=+890.3 kJ mol-1

Based on the above thermochemical equations, the value of ΔrHo at 298 K for the reaction

Cgraphite+2H2gCH4g will be:
HARD
For complete combustion of ethanol,
C 2 H 5 OH l + 3 O 2 g 2 CO 2 g + 3 H 2 O l ,
the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol -1 at 2 5 . Assuming ideality the Enthalpy of combustion, Δ c H , for the reaction will be: R = 8.314 kJ mol -1
MEDIUM
The combustion of benzene l gives CO2g and H2Ol. Given that heat of combustion of benzene at constant volume is -3263.9 kJ mol-1 at 25°C; the heat of combustion in kJ mol-1 of benzene at constant pressure will be

R=8.314 JK-1 mol-1